Https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-data-statistics/cc-6th/v/calculating-interquartile-range-iqr
This is a link that I gave to my little sister that helped her understand what interquartile range is. It has an example as well! I hope this helps!
What you’re doing is breaking it down into its parts and writing it into an equation that way long hand.
3 + .4 + .00 + .005
Answer:
(-1, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Terms/Coefficients
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = 2x + 3
y = x + 2
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 2x + 3 = x + 2
- [Subtraction Property of Equality] Subtract <em>x</em> on both sides: x + 3 = 2
- [Subtraction Property of Equality] Subtract 3 on both sides: x = -1
<u>Step 3: Solve for </u><em><u>y</u></em>
- Substitute in <em>x</em> [Original Equation]: y = -1 + 2
- Add: y = 1
Answer:
A=50.26548246units^2
Step-by-step explanation:
Radius is 4 because half the diameter (8) is the radius (4)
A=πr^2
A=π(4)^2
A=50.26548246units^2