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4 years ago

-| 15| simplify the expression

Mathematics

2 answers:

elena-s [515]4 years ago

6 0

<em>ANSWER:</em>

Absolute signs are signs that tell the number away from 0. So the absolute number cannot be negative. |x| = x. You don't know if the number was positive or negative. |-x|. |-x| is x since it tells it's x away from 0. -|x| is -x. Since the negative sign isn't in the absolute signs, you keep it as -15.

Hope this helps :D

Viefleur [7K]4 years ago

5 0

Answer:

-15

Step-by-step explanation:

The negative is outside of the absolute value signs/lines. The absolute value is how far the number is from 0. So, it doesn't matter whether or not there is a negative sign inside of the absolute value lines it will always be positive. But, if it's outside of it, then it will be negative.

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3 years ago

what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible

zheka24 [161]

The quotient when $\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$ in simplified form is $\frac{-(x+1)}{(x-1)(x+3)}$

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

$\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$

$=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}$

The quotient when $\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$ in simplified form is $\frac{-(x+1)}{(x-1)(x+3)}$

Find out more on equation at: brainly.com/question/2972832

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2 years ago

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Well, you can do it these two methods⬇

1) ⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇
2 and 1/3 (which is also written as 2 1/3)
⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆

⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇
Theres only one way, but if you're putting it as a decimal then you just divide 7 from 3 to get your answer
⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆

•So, 7 ÷ 3 = 2.3
•And 2(3) + 1 = 7 / 3 (if that makes sense)

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3 years ago

Mr. Akika has 49 21 cent and 31 cent stamps all told. The stamps are worth $13.39. how many of each kind of stamps does he have?

Lana71 [14]

Mr Akika has 18 21-cent stamp and 31 31-cent stamp.

He has 49 21-cent and 31-cent stamps all told.

let

x = number of 21 cent stamp

y = number of 31 cent stamp

Therefore,

<h3>Total number of stamp:</h3>

x + y = 49

<h3>Total cost of stamp:</h3>

21x + 31y = 1339

Therefore,

x + y = 49

21x + 31y = 1339

21x + 21y = 1029

10y = 310

y = 310 / 10

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Therefore,

x = 49 - 31

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Therefore, Mr Akika has 18 21-cent stamp and 31 31-cent stamp.

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2 years ago