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3 years ago

15

A space for storing boxes is 36 inches high. Each box is 6 inches high. A space of 9 inches must be left at the top. what is the

maximum number of boxes that can be stacked in this space?

1 answer:

Dvinal [7]3 years ago

7 0

Answer:

Step-by-step explanation: 36-9 equals 27. You can only fit 4 evenly so thats the answer

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Find the critical value tc for the confidence level c=0.98 and sample size n=18

Mariulka [41]

Answer step-by-step explanation:

We know that the critical t value for a 98% confidence level for a sample of size n = 18:

Finding degrees of freedom (n-1) = 17

-search the information in table t for 0.98 and find that t = 2.567

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3 years ago

7.2x14.3 what is that?

Galina-37 [17]

Answer:

102.96

Step-by-step explanation:

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2 years ago

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Given f(x) = –7x + 9 and h(x) = –5(–7x + 9), what are the slope and y-intercept of the graph of function h?

taurus [48]

The Slope of f(x) = –7x + 9 is (-7)

The slope of h(x) = –5(–7x + 9) is (35)

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3 years ago

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What is the area of the sector with a central angle of 49° and a radius of 11 cm? Use 3.14 for pi and round your final answer to

olga_2 [115]

Answer:

$\boxed{\text{51.71 cm}^{2}}$

Step-by-step explanation:

If the angle θ is in radians, the formula for the area (A) of a sector of a circle is

A = ½r²θ

If θ is in degrees

$A = \dfrac{1}{2}r^{2}\theta \times \dfrac{\pi \text{ rad}}{180^{\circ}}= \pi r^{2}\times\dfrac{\theta }{360}$

Data:

θ = 49°

r = 11 cm

Calculation:

$\begin{array}{rcl}A& = &3.14\times 11^{2}\times\dfrac{49}{360}\\\\ & = &3.14 \times 121 \times 0.1361\\ & = & \mathbf{51.71}\\\end{array}\\\text{The area of the sector is }\boxed{\textbf{51.71 cm}^{2}}$

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3 years ago

Which of the following is the correct way to write seventy million as a numeral?

Inessa05 [86]

Which of the following is the correct way to write seventy million as a numeral?

As I see no choices the right way to write seventy million as a numeral is

$70,000,000$

Hope I helped!

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3 years ago