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elena-s [515]
3 years ago
14

An animal shelter houses cats, dogs​, and rabbits. There are 126 animals at the shelter. Of the​ animals, 1/3 are cats. 5/6 of t

he remaining animals are dogs. How many of the animals are rabbits​?
Mathematics
2 answers:
Marat540 [252]3 years ago
6 0

Answer: 14 rabbits

42 - cats 70-dogs 112 animal dogs an dacts

Step-by-step explanation:

Rufina [12.5K]3 years ago
5 0

Answer:

There are 42 cats. And there are 63 dogs. 63 dogs plus 42 cats is 105 animals. 126 minus 105 is 21. Therefore, there are only 21 rabbits.

Step-by-step explanation:

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Find the difference in simplest form for 3/5-1/7
morpeh [17]

Answer: 0.457

multiply 3 by 7, and get 21

multiply 1 by 5, and get 5.

5 × 7 = 35.

fraction: 21/35 and 5/35

Subtract the numerators

21 − 5 = 16 = 16/35

Now we need to simplify the fraction that we have.

17 is larger than 16. So we're done reducing numbers.

<em>Our final answer: </em>16/35<em />

Hope this helps!

I am joyous to assist anytime.

<em>~Jarvis</em>

<em />

<em>  </em>

8 0
3 years ago
Can somebody please help me​
Westkost [7]
-5 = n + 14
So, n = -19
4 0
3 years ago
The first week at Javier's new job he spent $12.48, $9.50, $10.25, $4.99, and $8.59 on lunch. In the second week, he spent $3 mo
Jlenok [28]

Answer:

$0.60

Step-by-step explanation:

The mean is the average. We add up all the numbers and divide by the number of numbers.

The total for 1st week is  $12.48+$9.50+$10.25+$4.99+$8.59 = $45.81

Now, the mean:

Mean = 45.81/5 = $9.162

2nd week's total is 3 more than last week's total, so 2nd week's total is:

45.81 + 3 = $48.81

Now, Mean:

Mean = 48.81/5 = $9.762

The increase is  9.762 - 9.162 = $0.60

6 0
3 years ago
Is it possible to divide <br> 0 by 27<br> ?
Mumz [18]

Answer:

No. Dividing by 0 is not rational, no number works.

5 0
3 years ago
Read 2 more answers
Does 5^9 x 6^7= 30^16 ?
Gemiola [76]

Yes. When solving a problem like this, multiply the base numbers normally, and add the exponents together.

If you need more help, comment below and I'd be happy to assist.

5 0
4 years ago
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