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3 years ago

Y = -5 y = -1/2x-2 Write your answer in coordinates

Mathematics

2 answers:

Flauer [41]3 years ago

6 0

Okay, so I'm assuming you want to know the intersection?

-5 = -1/2x - 2

-3 = -1/2x

1/2x = 3

x = 6

(6, -5)

velikii [3]3 years ago

5 0

-5= -1/2x -2
-3=-1/2
1/2x=3
X=6
So you’re final points are (6,-5)

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If g(x) = x2 + 2, find g(3). 9 8 11 6

cestrela7 [59]

Answer

Find out the value of g(3) by using the function g(x) = x² + 2 given in the question .

To proof

The function given in the question is

g(x) = x² + 2

Take x = 3

put x = 3 in the g(x) = x² + 2

than it becomes

g(3) = 3² + 2

solving the above

we get

g(3) = 9 + 2

g(3) = 11

Thus g(3) = 11 and option (c) is correct .

Hence proved

7 0

3 years ago

Read 2 more answers

I need help with C, thank you.

guapka [62]

Simple....

$\frac{3}{4} x\ \textless \ \frac{9}{2}$

x<6

This means that on your graph at 6 it's a circle (not colored in) and it goes to the left indefinitely...

Thus, your answer.

6 0

3 years ago

The student council has 10 members where 5 of the members are Seniors. They need to choose a President, Vice President, Secretar

natima [27]

Answer:

P=1/42.

Step-by-step explanation:

We know that the student council has 10 members where 5 of the members are Seniors. They need to choose a President, Vice President, Secretary and Treasurer. We calculate the probability that the President is a Senior:

We calculate the number of possible combinations:

$C_4^{10}=\frac{10!}{4!(10-4)!}=210$

Number of favorable combinations is 5.

Threfore, the probability is

P=5/210

P=1/42.

8 0

3 years ago

There are 10 balls in an urn, numbered from 1 to 10. If 5 balls are selected at random and their numbers are added, what is the

Kisachek [45]

Let $B_i$ denote the value on the $i$ -th drawn ball. We want to find the expectation of $S=B_1+B_2+B_3+B_4+B_5$ , which by linearity of expectation is

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(which is true regardless of whether the $X_i$ are independent!)

At any point, the value on any drawn ball is uniformly distributed between the integers from 1 to 10, so that each value has a 1/10 probability of getting drawn, i.e.

$P(X_i=x)=\begin{cases}\frac1{10}&\text{for }x\in\{1,2,\ldots,10\}\\0&\text{otherwise}\end{cases}$