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3 years ago

Plsss help !!!!!!!!!!!!!!!

Mathematics

2 answers:

spin [16.1K]3 years ago

5 0

For 38 I think it would be A and for 37 I'm not sure.

seropon [69]3 years ago

3 0

Problem 37

<h3>Answer: B. 4 & 1/4 gallons</h3>

-------------------

Work Shown:

The 3/4 and 1/2 add up to (3/4)+(1/2) = (3/4)+(2/4) = 5/4 = 1&1/4

The whole part 1 is then added to the other whole parts 1 and 2 to get 1+2+1 = 4

Overall, the grand total is 4 & 1/4

An alternative way is to convert each mixed number to a decimal to get 1&1/2 = 1+1/2 = 1+0.5 = 1.5 and 2&3/4 = 2+3/4 = 2+0.75 = 2.75

Add up those decimals 1.5+2.75 = 4.25

then convert that result to a mixed number: 4.25 = 4+0.25 = 4+1/4 = 4&1/4

================================================

Problem 38

<h3>Answer: C. Cubic feet</h3>

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The units for volume follow the template "Cubic _____" where you'll write "feet", "inches", "centimeters" or whatever unit you are using in the blank.

Some other examples:

* cubic miles

* cubic meters

* cubic yards

You might be interested in

The FDA recommends that Americans get on average 3,000mg of salt in their daily diet. Suppose that you are interested in testing

gavmur [86]

Answer:

Null hypothesis; H0: μ = 3000

Alternative Hypothesis; Ha: μ ≠ 3000

Step-by-step explanation:

We are told that the FDA recommends that Americans get on average 3,000mg of salt in their daily diet.

Now we want to test this claim of whether Americans truly get an average of 3,000mg of salt in their daily diet.

Thus, the hypotheses is as follows;

Null hypothesis; H0: μ = 3000

Alternative Hypothesis; Ha: μ ≠ 3000

5 0

4 years ago

A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer

Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

$L_A \to$ length of play area A

$W_A \to$ width of play area A

$L_B \to$ length of play area B

$W_B \to$ width of play area B

$x \to$ Area of A

$y \to$ Area of B

From the question, we have the following:

$L_A = 1 + 4W_A$

$W_B = 2 + W_A$

$L_B = 2 + 3W_B$

$x = y$

The area of A is:

$x = L_A * W_A$

This gives:

$x = (1 + 4W_A) * W_A$

Open bracket

$x = W_A + 4W_A^2$

The area of B is:

$y = L_B * W_B$

$y = (2 + 3W_B) * ( 2 + W_A)$

Substitute: $W_B = 2 + W_A$

$y = (2 + 3(2 + W_A)) * ( 2 + W_A)$

Open brackets

$y = (2 + 6 + 3W_A) * ( 2 + W_A)$

$y = (8 + 3W_A) * ( 2 + W_A)$

Expand

$y = 16 + 8W_A + 6W_A + 3W_A^2$

$y = 16 + 14W_A + 3W_A^2$

We have that:

$x = y$

This gives:

$W_A + 4W_A^2 = 16 + 14W_A + 3W_A^2$

Collect like terms

$4W_A^2 - 3W_A^2 + W_A -14W_A - 16 =0$

$W_A^2 -13W_A - 16 =0$

Using quadratic calculator, we have:

$W_A = -14.1$ or $W = 1.13$ --- approximated

But the width can not be negative; So:

$W = 1.19$

7 0

3 years ago

If you draw a card with a value of 4 or less from a standard deck of cards, I will pay you 165$ if not your pay me $45. (Aces ar

jekas [21]

Answer: The required expected value is $3.46.

Step-by-step explanation:

Since we have given that

Number of value of 4 or less are

2,3,4

So, there are 12 in numbers.

So, probability would be

$\dfrac{12}{52}$

Since Aces are considered as the highest card in the deck.

So, remaining probability would be

$\dfrac{40}{12}$

Amount paid or value of 4 or less = $165

Amount not paid for other case = $45

So, the expected value would be

$\dfrac{12}{52}\times 165-\dfrac{40}{52}\times 45\\\\=\dfrac{1980}{52}-\dfrac{1800}{52}\\\\=\dfrac{180}{52}\\\\=3.46$

Hence, the required expected value is $3.46.

7 0

3 years ago

What is the scientific notation for this number: .0765 <br> show how you got yoru answer

Daniel [21]

Hey there!!

Scientific notation for 0.0765 is

... 7.65 × 10^-2

Hope my answer helps!!

5 0

3 years ago

Read 2 more answers

36-40. The probability that a fatal car accident is alcohol related is over 40%. The probability that a fatal accident happens a

Nataliya [291]

Drivers should not drink and drive. I hope this helps if not hopefully someone helps out

4 0

3 years ago

Plsss help !!!!!!!!!!!!!!!​

Plsss help !!!!!!!!!!!!!!!