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Hitman42 [59]
3 years ago
6

If f(x) is a linear function, which statement must be true? f(x) has no constant term. f(x) has no x2-term. f(x) has no terms wi

th a coefficient other than 1. f(x) has no x-term.
Mathematics
1 answer:
Dafna11 [192]3 years ago
6 0

Answer:f(x) has no x^2 term.

Step-by-step explanation:

You might be interested in
Add 4/5 + 1/4 visually!
Greeley [361]

Answer:

1 and 1/20

Step-by-step explanation:

LCM of 5 and 4 = 20

4/5 = 16/20

1/4 = 5/20

6 0
3 years ago
Which relation represents f(x) = 2x - 5?
goblinko [34]

Answer:

{(0,-5), (1, -3), (2, -1), (3, 1)

Step-by-step explanation:

If you plug in 1 for x you get f(x)=2(1)-5 which equals 2-5=-3

You would repeat these steps just going up by one number every time

7 0
4 years ago
Help me pleaseeeeeeeeeeee
JulsSmile [24]

Answer:

3.643 X 10 -1

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which of the followinkg is a rational number that is not an integer?<br> -2<br> -0.5<br> 0<br> 4
g100num [7]
It’s -0.5 because it an integer has to be whole number hope this helps :)
6 0
3 years ago
If outliers are discarded, then the retirement savings by residents of Econistan is normally distributed with a mean of $100,000
zavuch27 [327]

Answer:

P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.85)=1-P(z

The firgure attached illustrate the problem

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the retirement savings of a population, and for this case we know the distribution for X is given by:

X \sim N(100000,20000)  

Where \mu=100000 and \sigma=20000

We are interested on this probability

P(X>117000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.85)=1-P(z

The firgure attached illustrate the problem

7 0
3 years ago
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