The further left a number is the less it is
The further right a number is the greater it is
The sum of the function will be (r – s)(x) = –2x² + x – 3, The difference of the function will be (r – s)(x) = –2x² + x – 3, and The product of the function will be (r × s)(x) = 2x³ – 6x².
The complete question is attached below.
<h3>What is Algebra?</h3>
The analysis of mathematical representations is algebra, and the handling of those symbols is logic.
The functions are given below.
r(x) = x – 3
s(x) = 2x²
The sum of the function will be
(r + s)(x) = x – 3 + 2x²
(r + s)(x) = 2x² + x – 3
The difference of the function will be
(r – s)(x) = (x – 3) – 2x²
(r – s)(x) = –2x² + x – 3
The product of the function will be
(r × s)(x) = (x – 3) (2x²)
(r × s)(x) = 2x³ – 6x²
More about the Algebra link is given below.
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Answer:
The width of the field is 4x + 20 / x² -2x -3 yards
Step-by-step explanation:
The area of a rectangular field is given by the following formula:
area = length*width
In this case we want to find the width of this field, therefore if we isolate the width in the expression above we will have a suitable expression:
width*length = area
width = area / length
So applying the data from the problem, we have:
width = [(2x + 6)/(x + 1)] / [(x² - 9)/(2x + 10)]
width = [(2x + 6)/(x + 1)]*[(2x + 10)/(x² - 9)]
width = 2(x + 3)*(2x + 10) / (x+1)*(x - 3)*(x + 3)
width = 2*(2x + 10) / (x + 1)*(x - 3)
width = 4x + 20 / x² -2x -3
Answer:
the selling price of the goods is ₹6,00,000
Step-by-step explanation:
The computation of the selling price of the goods are shown below:
As we know that
Selling price = Cost price + profit
= 5,00,000 + 5,00,000 × 0.20
= 5,00,000 + 1,00,000
= ₹6,00,000
Hence, the selling price of the goods is ₹6,00,000
