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3 years ago

6

A square has sides of length s a rectangle is 6 inches shorter and 1 inch longer than the square. Which of the following polynom

ials represents the area of the rectangle? select all that apply
s^2

(s+6)(s+1)

(s-6)(s-1)

s^2-7s+1

s^2-5s-6

s^2+7s+6

1 answer:

harkovskaia [24]3 years ago

5 0

I think the answer is C

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Alan multiplies a 4-digit number by 36. How can you tell the

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First, we must establish that a 4-digit number will have 4 place values namely;

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And since, 36 has 2 place values;

We can conclude that the number of partial products that Alan wil have is; 2× 4 = 8.

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2 years ago

Use the cubic model y=10x^3-12x to estimate the value of y when x=3

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A class at Middlebury school collected date on the types of movies students prefer. Complete each statement using the table.

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Based on the information of the table, you have:

1. The ratio is 105/150. By simplifying you get for the ratio 7/10.

2. The students that prefer action movies are 75+90 = 165 and the total numbe of students is 180+240 = 420. Then, the fraction of students who prefer action movies is:

165/420 = 11/28

3. The fraction of seventh graders students that prefer action movies is:

75/180 = 5/12

4. The percent of student that prefer comedy is:

105 + 150 = 255 total student that prefer comedy

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the fraction is:

(x/100)420 = 255

solve for x:

x = 255(100/420)

x = 60.71

the percent of students is 60.71%

5. The percent of eighth graders student who prefer action moveis is:

(x/100)240 = 90

x = 90(100/240)

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the percent of students is 37.5%

6. To determine which from the given grades has the greatest percent of student that prefer action movies, calculate the percent of student in seventh-grade:

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1 year ago

The time taken to deliver a pizza has a uniform probability distribution from 20 minutes to 60 minutes. What is the probability

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Answer:

(1) The probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2a) The percentage of results more than 45 is 79.67%.

(2b) The percentage of results less than 85 is 91.77%.

(2c) The percentage of results are between 75 and 90 is 15.58%.

(2d) The percentage of results outside the healthy range 20 to 100 is 2.64%.

Step-by-step explanation:

(1)

Let <em>Y</em> = the time taken to deliver a pizza.

The random variable <em>Y</em> follows a Uniform distribution, U (20, 60).

The probability distribution function of a Uniform distribution is:

$f(x)=\left \{ {{\frac{1}{b-a};\ x\in [a, b] } \atop {0};\ otherwise} \right.$

Compute the probability that the time to deliver a pizza is at least 32 minutes as follows:

$P(Y\geq 32)=\int\limits^{60}_{32} {\frac{1}{b-a} } \, dx \\=\frac{1}{60-20} \int\limits^{60}_{32} {1 } \, dx\\=\frac{1}{40}\times[x]^{60}_{32}\\=\frac{1}{40}\times[60-32]\\=0.70$

Thus, the probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2)

Let <em>X</em> = results of a certain blood test.

It is provided that the random variable <em>X</em> follows a Normal distribution with parameters $\mu = 60$ and $s = 18$ .

The probabilities of a Normal distribution are computed by converting the raw scores to <em>z</em>-scores.

The <em>z</em>-scores follows a Standard normal distribution, N (0, 1).

(a)

Compute the probability that the results are more than 45 as follows:

$P(X>45)=P(\frac{X-\mu}{\sigma}> \frac{45-60}{18})=P(Z>-0.833)=P(Z$

The percentage of results more than 45 is: $0.7967\times100=79.67\%$

Thus, the percentage of results more than 45 is 79.67%.

(b)

Compute the probability that the results are less than 85 as follows:

$P(X$

The percentage of results less than 85 is: $0.9177\times100=91.77\%$

Thus, the percentage of results less than 85 is 91.77%.

(c)

Compute the probability that the results are between 75 and 90 as follows:

$P(75$

The percentage of results are between 75 and 90 is: $0.1558\times100=15.58\%$

Thus, the percentage of results are between 75 and 90 is 15.58%.

(d)

Compute the probability that the results are between 20 and 100 as follows:

$P(20$

Then the probability that the results outside the range 20 to 100 is: $1-0.9736=0.0264$ .

The percentage of results outside the range 20 to 100 is: $0.0264\times100=2.64\%$

Thus, the percentage of results outside the healthy range 20 to 100 is 2.64%.

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3 years ago