Since we know the degrees of the circle is 360, add all of the pieces together and set equal to 360
Solving you get x = 15.
When plugging 15 back into each expression we get 90, 160, and 110.
This means the triangle sides are all different so the triangle is scalene.
Look at the picture.
The polygon is a right-angled trapezoid.
The area is:

The points (-2,-1) and (6,-1) lie on the same horizontal line, so the distance between them is 6-(-2)=6+2=8. The length of a is 8 units.
The points (-2,5) and (3,5) lie on the same horizontal line, so the distance between them is 3-(-2)=3+2=5. The length of b is 5 units.
The points (-2,5) and (-2,-1) lie on the same vertical line, so the distance between them is 5-(-1)=5+1=6. The length of h is 6 units.

The area is
39 square units.
Answer:
^(3)+7x^(2)+4x-12
Step-by-step explanation:
Answer:

Step-by-step explanation:
Define a cyclic quadrilateral by a quadrilateral that is circumscribed by a circle. In this case, since the quadrilateral shown is circumscribed by a circle, it is a cyclic quadrilateral.
A property of all cyclic quadrilaterals is that their opposite angles are supplementary, meaning they add up to 180 degrees. Since
and
are opposite angles in the quadrilateral, they must be supplementary. Therefore, we have the equation:

So you have x, then you square it to get x^2, then you minus 2x, then +3
The inverse is going backwards so you -3 then +2x then square root x
So you get square root x + 2x -3
I'm pretty sure this is right, sorry if I'm wrong.