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Dafna1 [17]
2 years ago
12

Right to explain how this digit 6 changes value in number 666, 666, 666

Mathematics
1 answer:
zvonat [6]2 years ago
8 0
To a higher number the six changes value in this number above
You might be interested in
What is the radius and center of the circle given by the equation (x-5)^{2}+(y+2)^{2} = 81/4
artcher [175]

Answer:

The center is (5, -2) and the radius is 9/2

Step-by-step explanation:

The equation of a circle can be written by

(x-h) ^2 + (y-k)^2 = r^2

where (h,k) is the center and r is the radius

(x-5)^{2}+(y+2)^{2} = 81/4

( (x-5)^{2}+(y- -2)^{2} = (9/2)^2

The center is (5, -2) and the radius is 9/2

6 0
3 years ago
Events A and B have probabilities such that P(A) = 0.3, P(B) = 0.25, P(M ∪ N) = 0.425, and P(M ∩ N) = 0.075. Are events A and ev
nekit [7.7K]

Answer:

(C)Yes, because P(M) ∙ P(N) = P(M ∩ N)

Step-by-step explanation:

Two events A and B are independent if P(A)P(B)=P(A ∩ B)

Given events A and B such that:

P(A) = 0.3, P(B) = 0.25, P(A ∪ B) = 0.425, and P(A ∩ B) = 0.075

  • P(A)P(B)=0.3 X 0.25 =0.075
  • P(A ∩ B) = 0.075

Since the two expression above gives the same answer, they are independent.

<u>The correct option is C.</u>

7 0
3 years ago
Find the present value of $10,000 payable in five years at 6% simple interest.
Svet_ta [14]
We know, I = P * R * T /100
Here, P = 10,000
R = 6%
T = 5

Substitute their values into the expression,
I = 10000 * 6 * 5 /100
I = 300000 / 100
I = 300

Final Amount = Initial Amount + Interest Amount
Final Amount = 10,000 + 300 = 10,300

So, your final answer is $10,300

Hope this helps!

6 0
3 years ago
Find the product of (4x+1)(5x-2)
Bad White [126]

Answer:

20x²-3x-2

Step-by-step explanation:

(4x+1)(5x-2)

20x²-8x+5x-2

20x²-3x-2

4 0
3 years ago
Fill in the missing portions of the function to rewrite g(x) = 3a^2 − 42a + 135 to reveal the zeros of the function. What are th
mariarad [96]

Answer:

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

g(x) = 3x^{2} - 42a + 135

So

a = 3, b = -42, c = 135

\bigtriangleup = (-42)^{2} - 4*3*135 = 144

x_{1} = \frac{-(-42) + \sqrt{144}}{2*3} = 9

x_{2} = \frac{-(42) - \sqrt{144}}{2*3} = 5

So

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

8 0
3 years ago
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