Answer:
when the rubber band is realeased the potential energy is quickly converted to kinetic energy this is equal to one mass of the the rubber band multiplied by its velocity( in meters per second)
Answer:
19.2 m/s
Explanation:
The train is moving at 18 m/s and you are walking in the same direction (east) so the speeds are added
18 + 1.2 = 19.2
If you were walking backwards (west) your velocity with respect to the ground would be
18 - 1.2 = 16.8
The strength of the electric field on the point charge at this distance will be 4000 V/m.
<h3>What is the strength of the electric field?</h3>
The strength of the electric field is the ratio of electric force per unit charge.
The given data in the problem is;
Qis the unit charge = 4.0 × 10⁻⁶ C
E is the strength of the electric field
R is the distance from point charge = 3 m
The strength of the electric field is;

Hence, the strength of the electric field on the point charge at this distance will be 4000 V/m.
To learn more about the strength of the electric field refer to the link;
brainly.com/question/15170044
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Examples of Newton's Second Law of Motion
Pushing a Car and a Truck. ...
Pushing a Shopping Cart. ...
Two People Walking Together. ...
Hitting a Ball. ...
Rocket Launch. ...
Car Crash. ...
Object thrown from a Height. ...
Karate Player Breaking Slab of Bricks.
Answer:
<h2>
t=1.43 s</h2>
Option A is the correct option.
Solution,
S=10 m
u=0 m/s
a=9.8 m/s^2
Now,
<h3>

</h3>
hope this helps...
Good luck on your assignment...