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grandymaker [24]
3 years ago
6

HELP PLEASE! WILL GIVE BRAINLY GIVE THANKS!!!! I chose A roller coaster

Physics
1 answer:
kolezko [41]3 years ago
3 0

I am working off the second image you attached, specifically am looking at the roller coaster ride depicted there, having two hills (first higher) and one valley.

(a) The greatest potential energy (Ep) is on top of the first hill. The greatest kinetic energy (Ek) is found in the valley. I am assuming they are asking for the two extremes at separate spots.

(b) The smallest Ep of the cart is found when it is in the valley. The smallest Ek is found at the top of the first hill (right before it starts moving)

(c) If "falls" refers to the ride moving downhill, then the following changes occur: Ep is going down (decreasing), Ek is going up (increasing).

(d) the sum of Ek and Ep, aka total mechanical energy, remains constant.

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What energy transfer will a stretched rubber band have when let go
GarryVolchara [31]

Answer:

when the rubber band is realeased the potential energy is quickly converted to kinetic energy this is equal to one mass of the the rubber band multiplied by its velocity( in meters per second)

3 0
3 years ago
You are on a train traveling east at speed of 18 m/s with respect to the ground. 1) If you walk east toward the front of the tra
dlinn [17]

Answer:

19.2 m/s

Explanation:

The train is moving at 18 m/s and you are walking in the same direction (east) so the speeds are added

18 + 1.2 = 19.2

If you were walking backwards (west) your velocity with respect to the ground would be

18 - 1.2 = 16.8

8 0
4 years ago
A point charge is placed 3m from a 4uc charge what is the strength of the electric field on the point charge at this distance ro
Vlada [557]

The strength of the electric field on the point charge at this distance will be 4000 V/m.

<h3>What is the strength of the electric field?</h3>

The strength of the electric field is the ratio of electric force per unit charge.

The given data in the problem is;

Qis the unit charge = 4.0 × 10⁻⁶ C

E is the strength of the electric field

R is the distance from point charge = 3 m

The strength of the electric field is;

\rm E = \frac{KQ}{R^2} \\\\ \rm E = \frac{9 \times 10^9 \times 4 \times 10^{-6} \ C}{3^2} \\\\ E= 4000 V/m

Hence, the strength of the electric field on the point charge at this distance will be 4000 V/m.

To learn more about the strength of the electric field refer to the link;

brainly.com/question/15170044

#SPJ1

7 0
2 years ago
4. List 3 detailed examples that illustrate Newton's 2nd Law.
NNADVOKAT [17]

Examples of Newton's Second Law of Motion

Pushing a Car and a Truck. ...

Pushing a Shopping Cart. ...

Two People Walking Together. ...

Hitting a Ball. ...

Rocket Launch. ...

Car Crash. ...

Object thrown from a Height. ...

Karate Player Breaking Slab of Bricks.

3 0
2 years ago
If you jump off a 10 m diving platform, how long will it take you to hit the water?
Vilka [71]

Answer:

<h2>t=1.43 s</h2>

Option A is the correct option.

Solution,

S=10 m

u=0 m/s

a=9.8 m/s^2

Now,

<h3>2s = a {t}^{2}  \\ or \:  {t}^{2}  =  \frac{2 \times 10}{9.8}  \\ or \:  {t}^{2}  =  \frac{20}{9.8}  \\ or \:  {t}^{2}  = 2.04 \\ or \: t =  \sqrt{2.04}  \\ t = 1.43 \: seconds</h3>

hope this helps...

Good luck on your assignment...

8 0
3 years ago
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