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melisa1 [442]
3 years ago
8

Please help! thank you​

Physics
1 answer:
BlackZzzverrR [31]3 years ago
8 0

Answer:

poor, too precise

good

good

good

Explanation:

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What is the energy in joules of a photon with a frequency of 3.16e 12 s-1?
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We have: Energy(E) = Planck's constant(h) × Frequency(∨)
Here, Planck's constant(h) = 6.626 × 10⁻³⁴ J/s
Frequency (∨) = 3.16 × 10¹² /s

Substitute the values into the expression:
E = (6.626 × 10⁻³⁴)(3.16 × 10¹²) J
E = 2.093 × 10⁻²¹ Joules

In short, Your Final answer would be 2.093 × 10⁻²¹ J

Hope this helps!
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During the fall, all the initial potential energy of the rock 
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