Answer:
The distance away the center of the earthquake is 1083.24 km.
Explanation:
Given that,
Speed of transverse wave = 9.1\ km/s
Speed of longitudinal wave = 5.7 km/s
Time = 71 sec
We need to calculate the distance of transverse wave
Using formula of distance

....(I)
The distance of longitudinal wave
....(II)
From the first equation

Put the value of t in equation (II)




Hence, The distance away the center of the earthquake is 1083.24 km.
Answer:
Explanation:
Given:
Initial velocity, u = 0 m/s (at rest)
Final velocity, v = 22 m/s
Time, t = 9 s
Diameter, d = 58 cm
Radius, r = 0.29 m
Using equation of motion,
v = u + at
a = (22 - 0)/9
= 2.44 m/s^2
v^2 = u^2 + 2a × S
S = (22^2 - 0^2)/2 × 2.44
= 99.02 m
S = r × theta
Theta = 99.02/0.29
= 341.44 °
1 rev = 360°
341.44°,
= 341.44/360
= 0.948 rev
= 0.95 rev
B.
Final angular speed, wf = v/r
= 22/0.29
= 75.86 rad/s
This is called average speed.Its really simple
35%
5.43/15.6
This is how you calculate the percentage the answer is 35%