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enot [183]
3 years ago
11

20. Evaluating Data You are looking at a star through a telescope in January.

Physics
1 answer:
REY [17]3 years ago
5 0
It is c I took the test
You might be interested in
Cual es el esfuerzo que puede provocar un corte en el material
jolli1 [7]

Answer:

El esfuerzo cortante, de corte, de cizalla o de cortadura es el esfuerzo interno o resultante de las tensiones paralelas a la sección transversal de un prisma mecánico como por ejemplo una viga o un pilar. Se designa variadamente como T, V o Q.

Este tipo de solicitación formado por tensiones paralelas está directamente asociado a la tensión cortante. Para una pieza prismática se relaciona con la tensión cortante mediante la relación:

(1){\displaystyle Q_{y}=\int _{\Sigma }\tau _{xy}\ dydz,\qquad Q_{z}=\int _{\Sigma }\tau _{xz}\ dydz,\qquad Q={\sqrt {Q_{y}^{2}+Q_{z}^{2}}}}

Para una viga recta para la que sea válida la teoría de Euler-Bernoulli se tiene la siguiente relación entre las componentes del esfuerzo cortante y el momento flector:

5 0
4 years ago
Una cámara fotográfica analógica (no digital) tiene dos lentes intercambiables. Uno de foco 55mm y el otro de 200 mm. Toma una f
Sergeu [11.5K]

Answer:

f = 55mm,     h ’= -9.89 cm

f = 200 mm,  h ’= 42.5 cm

Explanation:

For this exercise let's start by finding the distance to the image, using the equation of the constructor

         \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

where f is the focal length, p and q are the distances to the object and image, respectively

lens with f₁ = 55mm = 0.55cm

         \frac{1}{q} = \frac{1}{f} - \frac{1}{p}

         \frac{1}{q_1} = \frac{1}{0.55} - \frac{1}{10}

          \frac{1}{q_1} = 1.718

          q₁ = 0.582 m

lens with f₂ = 200mm = 2m

           \frac{1}{q_2} =   \frac{1}{2} - \frac{1}{10}

            \frac{1}{q_2} = 0.4

            q₂ = 2.5 m

the magnification of a lens is given by

            m = \frac{h'}{h} = -  \frac{q}{p}

             h ’= - \frac{q}{p} \ h

let's calculate for each lens

f = 55mm

             h '= - 0.582 / 10 1.7

             h ’= 0.0989 m

             h ’= -9.89 cm

f = 200 mm

             h '= - 2.5 / 10 1.7

             h ’= -0.425 m

             h ’= 42.5 cm

The negative sign indicates that the image is real and inverted

4 0
3 years ago
If someone is whispering, but you cant hear them, how do you fix that problem?
Readme [11.4K]
The answer is C
Hope this helps!
6 0
4 years ago
Read 2 more answers
The velocity of a 640-kg auto is changed from 10.0 m/s to 44.0 m/s in 71.0 s by an external, constant force. (a) What is the res
n200080 [17]

Answer:

(a) <em>change in momentum of the car = 21760 kgm/s</em>

(b) <em>The magnitude of the force = 306.48 N</em>

Explanation:

<em>(a)</em>

<em>Change in momentum: </em><em>This is the product of mass and change in velocity. The unit of momentum is kgm/s. It can be expressed mathematically as,</em>

Change in momentum of the car = m(v-u)................. Equation 1

Where m = mass of the car, v = final velocity of the car, u = initial velocity of the car.

<em>Given: m = 640 kg, v = 44.0 m/s, u = 10.0 m/s.</em>

<em>Substituting these values into equation 1,</em>

<em>Change in momentum of the car = 640 (44-10)</em>

<em>change in momentum of the car = 640× 34</em>

<em>change in momentum of the car = 21760 kgm/s</em>

<em>change in momentum of the car = 21760 kgm/s</em>

<em>(b) Force:</em><em> Force of a body can be defined as the product of mass and its acceleration. It is measured in Newton (N). It can be expressed mathematically as,</em>

<em>Force = ma ................................ Equation 2</em>

<em> </em><em>    Or</em>

<em>Force = m(v-u)/t...................................... Equation 3</em>

<em>Where m = mass of the car, v = final velocity of the car, u = initial velocity of the car, a = acceleration of the car, t = time taken to change the velocity.</em>

<em>Given: m = 640 kg, u = 10.0 m/s v = 44 m/s, t = 71 s.</em>

<em>Substituting these values into equation 3</em>

<em>Force = 640(44-10)/71</em>

<em>Force = (640×34)/71</em>

<em>Force = 306.48 N</em>

<em>The magnitude of the force = 306.48 N</em>

3 0
3 years ago
Earth’s crust continuously melts and solidifies in the upper mantle. Why does oceanic crust solidify faster than continental cru
Softa [21]

The oceanic crust solidifies faster than the continental crust. Because when magma comes into contact with ocean water it cools faster than when it reaches continental rock. Option C is correct.

<h3>What is the crust?</h3>

The outermost layer of a terrestrial planet is referred to as its "crust."

In the upper mantle, the Earth's crust is constantly melting and solidifying. Compared to magma beneath the continental crust, the oceanic crust has a lower temperature.

Magma cools more quickly when it comes into touch with ocean water than when it hits continental rock. causes the continental crust to solidify more slowly than the oceanic crust.

Hence option C is correct.

To learn more about the crust refer;

brainly.com/question/13428623

#SPJ1

3 0
2 years ago
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