3 years ago

Question 2

Mathematics

1 answer:

Masteriza [31]3 years ago

6 0

1.1, 0.10299, 0.1038, 0.9 im pretty sure

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Find the volume <br> 6ft<br> 4ft<br> 3ft<br> (i know it’s not 72)

vlada-n [284]

Answer:

$\fbox{Volume \: of \: pyramid \: = 24 ft³}$

Step-by-step explanation:

Given:

shape of object = Pyramidal

length of base l= 4ft

width of base w = 3ft

height of pyramid h = 6 ft

To find:

volume of pyramid = ?

Solution:

$Volume \: of \: pyramid= \frac{l \times w \times h}{3} \\ Volume \: of \: pyramid= \frac{6 \times 4 \times 3}{3} \\ Volume \: of \: pyramid= \frac{24 \times \not3}{ \not3} \\ Volume \: of \: pyramid= 24 \: {ft}^{3}$

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JKLM is a rhombus. KM is 10 and JL is 24. Find the perimeter of the rhombus.

Ahat [919]

Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
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c^2=169
thus;
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c=13 units;
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