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zalisa [80]
2 years ago
8

Amber is starting a garden. She plants 2 flowers the first month. The next month, she plans three times more flowers (6 flowers)

. Each month, Amber plants three times more flowers than the previous month. How many flowers will Amber plant in the 4th month? A. Write a number sentence. (2 × 4) + 2 + 6 = x Multiply 2 flowers by the 4th month, then add the number of flowers from the first and second month. B. Make a table. In the first row, write 1st month - 2 flowers. In the next row, write 2nd month - 3 flowers. In the third row, write 3rd month - 4 flowers. Continue the pattern to find how many flowers Amber will plant in the fourth month. C. Draw a diagram. Use dots to represent flowers. Draw 2 dots for the first month. Draw 6 dots for the next month. Do this two more times and keep tripling the previous number of flowers to find the number of flowers planted in the fourth month.
Mathematics
1 answer:
Artist 52 [7]2 years ago
6 0
This is a geometric progression problem. We can the general formula that can tell us how many flowers would be planted each month.
Let's write the terms that we know and see if we can find the pattern:

\begin{tabular}{lll}
Month & Number of flowers planted & Different form            \\
1     & 2                         & 2\cdot3^0 \\
2     & 6                         & 2\cdot3^1 \\
3     & 18                        & 2\cdot3^2 \\
4     & 54                        & 2\cdot3^3
\end{tabular}
\end{table}
The patern here is obvious. Let's write it down:
N=2\cdot3^{n-1}
This formula gives us a number of flowers planted in the n-th month.
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Nat2105 [25]

Answer:

d.

Step-by-step explanation:

if x varies directly as y,

x = ky

8 = 12k

12k = 8

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k = 2/3,

x = 2/3 y

now substitute the value of any of the numbers of each pair, and check if it works:

for e.g, find x when y = 15

x = 2/3y

x = 2/3 × 15

x = 10

since you obtain x = 10 when y = 15, the pair is a possible corresponding value of x and y. now do the same for the rest .

ii) x = 2/3y

x = 2/3 × 3, when y = 3

x = 2

hence, this is also a possible pair of x and y values.

iii) x = 2/3y

x = 2/3 × 9 when y = 9

x = 6

again, a possible pair of x and y values.

iv) x = 2/3y

x = 2/3 × 20 when y = 20

x = 40/3

here, when y = 20, x is not 15. it is 40/3.

thus, it can be determined that this is not a possible pair of x and y values.

please try to understand and have a great day!

8 0
2 years ago
Use the rules of significant figures to answer the following question: 22.674 • 15.05
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3 years ago
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faust18 [17]

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Then solve the equation

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5 0
1 year ago
Jenny bought a 5 notebooks and 2 pencils, and the total was 9 dollars.
weeeeeb [17]
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Now you would substitute it in:
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So your final answer is notebooks are $1.50 and pens are $0.75, I hope this helps!
6 0
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