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zalisa [80]
3 years ago
8

Amber is starting a garden. She plants 2 flowers the first month. The next month, she plans three times more flowers (6 flowers)

. Each month, Amber plants three times more flowers than the previous month. How many flowers will Amber plant in the 4th month? A. Write a number sentence. (2 × 4) + 2 + 6 = x Multiply 2 flowers by the 4th month, then add the number of flowers from the first and second month. B. Make a table. In the first row, write 1st month - 2 flowers. In the next row, write 2nd month - 3 flowers. In the third row, write 3rd month - 4 flowers. Continue the pattern to find how many flowers Amber will plant in the fourth month. C. Draw a diagram. Use dots to represent flowers. Draw 2 dots for the first month. Draw 6 dots for the next month. Do this two more times and keep tripling the previous number of flowers to find the number of flowers planted in the fourth month.
Mathematics
1 answer:
Artist 52 [7]3 years ago
6 0
This is a geometric progression problem. We can the general formula that can tell us how many flowers would be planted each month.
Let's write the terms that we know and see if we can find the pattern:

\begin{tabular}{lll}
Month & Number of flowers planted & Different form            \\
1     & 2                         & 2\cdot3^0 \\
2     & 6                         & 2\cdot3^1 \\
3     & 18                        & 2\cdot3^2 \\
4     & 54                        & 2\cdot3^3
\end{tabular}
\end{table}
The patern here is obvious. Let's write it down:
N=2\cdot3^{n-1}
This formula gives us a number of flowers planted in the n-th month.
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3 years ago
Find the area of the shaded region
kogti [31]

Answer:

  7. 183 in^2

  8. 192.42 m^2

  9. 239.4 ft^2

Step-by-step explanation:

7. The figure seems most easily seen as a trapezoid with a triangle removed. The trapezoid has bases of 26 and 14, and a height of 15. So, its area is ...

  A = (1/2)(b1 +b2)(h) = (1/2)(26+14)(15) = 300 . . . . . . square inches

The triangle has a base of 26 and a height of 9, so an area of ...

  A = (1/2)bh = (1/2)(26)(9) = 117 . . . . . . square inches

Then the shaded area is ...

  300 in^2 -117 in^2 = 183 in^2

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8. The area of the donut can be found different ways. One way is to multiply the width of the shaded area (3.5 m) by the circumference of its centerline.

The centerline diameter is 21 m - 3.5 m = 17.5 m, so the circumference of that circle is ...

  C = πd = π(17.5 m) = 17.5π m

Then the area of the shaded part is ...

  (3.5 m)(17.5π m) = 61.25π m^2 ≈ 192.42 m^2

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9. As in problem 7, this can be treated as a parallelogram less a triangle. Here, we need to do a little work to find the area of the triangle.

The triangle of interest is a right triangle with hypotenuse 23.8 ft and one leg 21 ft. The Pythagorean theorem can be used to find the other leg:

  h = √(23.8^2 -21^2) = √125.44 = 11.2

Then the area of the triangle is ...

  A = (1/2)bh = (1/2)(21)(11.2) = 117.6 . . . ft^2

The area of the parallelogram (including the triangle) is ...

  A = bh = (23.8 ft)(15 ft) = 357 ft^2

So, the shaded area is the difference ...

  357 ft^2 -117.6 ft^2 = 239.4 ft^2

_____

<em>Comment on significant digits</em>

The area in problem 8 may be considered to be 192.325 m^2 if you are required to use 3.14 as the value for pi. Since that value is only good to 3 significant digits, it is quite pointless to report the answer to 6 significant digits when using that value. It is quite reasonable to use 192 m^2 for the answer, especially if you're required to round to whole numbers.

8 0
3 years ago
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melamori03 [73]

Answer:

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Step-by-step explanation:

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= \bold{-1}

So, the appropriate value to complete it is -1

#CMIIW ^^

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An archery target consists of a circular bull's-eye with radius x, surrounded by four rings with width y. What is the area of th
amid [387]
<span>given:
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