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vladimir2022 [97]
4 years ago
14

a person enters a building on the first floor and runs up to the third floor in 30 seconds at this rate, how many seconds will i

t take the person to run from the first floor up to the 6th floor in the building?
Mathematics
1 answer:
Diano4ka-milaya [45]4 years ago
4 0
It will take 60 seconds. Because they went in at the first floor and ran up to the third in 30 seconds, if they go down and go up to the 6th floor it would be a minute, because 30+30 is 60
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Which expression is NOT equivalent to 6x + (5x + 10)?
kondor19780726 [428]
To find the answer test all the possible solutions
6x+(5x+10)
= 6x+5x+10
=11x+10

A) 11x+10

B) (6x+10)+5x
= 6x+10+5x
=11x+10

C) 5(x+10)+5x
= 5x+50+5x
= 10x+50, this is not equivalent. 

D) 6x+5(x+10)
= 6x+5x+50
= 11x+50, this is not equivalent either 
4 0
3 years ago
hello could you please help me with this math problem with full explanation which I am unable to solve? Thank you.
77julia77 [94]

c) 37.7cm

Hope this helps!! Give brainliest if possible.....Have a good day.

4 0
3 years ago
Please help, this is 7th grade math
Neporo4naja [7]

Answer:

its -1 and 3/4

Step-by-step explanation:

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5 0
4 years ago
Read 2 more answers
If f(x) = (x^1/2 - x)
Slav-nsk [51]
Well, you are subtracting g(x) from f(x) so:

√x-x-(2x^3-√x-x) which is:

√x-x-2x^3+√x+x  (you have your signs wrong at the bottom of your post)

Now you would simply combine like terms (do your addition and subtraction of like terms)

-2x^3+2√x

So the answer is D.
8 0
4 years ago
In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent (Pew Research, June 5, 2014). An independe
enot [183]

Answer:

a)

n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2, in which z is related to the confidence level.

b) A sample size of 991 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent

This means that \pi = 0.16

a. What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.03 (round up to the next whole number).

This is n for which M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = z\sqrt{\frac{0.16*0.84}{n}}

0.03\sqrt{n} = z\sqrt{0.16*0.84}

\sqrt{n} = \frac{z\sqrt{0.16*0.84}}{0.03}

(\sqrt{n})^2 = (\frac{z\sqrt{0.16*0.84}}{0.03})^2

n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2, in which z is related to the confidence level.

Question b:

99% confidence level,

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2

n = (\frac{2.575\sqrt{0.16*0.84}}{0.03})^2

n = 990.2

Rounding up

A sample size of 991 is needed.

8 0
3 years ago
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