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3 years ago

Translate to an inequality using the variable x. A number is less than 2, or greater than 6 and less than or equal to 9.

Mathematics

1 answer:

Dmitrij [34]3 years ago

8 0

Answer:

Please read the answers below

Step-by-step explanation:

Let's use x for writing the inequalities asked:

A number is less than 2:

x < 2

A number is greater than 6 and less than or equal to 9:

6 < x ≤ 9

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Which is bigger 3/4 or 2/3

tia_tia [17]

When we make it into a common denominator, find a common multiple between the denominators. For this instance, it is 3/4=9/12 2/3=8/12 When we see it with a common denominator, 3/4 is bigger than 2/3.

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To the nearest tenth, which is the BEST estimate for the volume of the given pyramid?

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Answer:

4.2 cubic inches

Step-by-step explanation:

Find the diagram attached

Volume of the rectangular pyramid = BH/3

B is the base area

H is the height of the pyramid

Given

Base area = 3.2in * 1.4in

Base area = 4.48sq. in

Height = 2.8in

Volume of the rectangular pyramid = 4.48*2.8/3

Volume of the rectangular pyramid = 12.544/3

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3 years ago

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Leno4ka [110]

Answer:

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Step-by-step explanation:

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3 years ago

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Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

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3 years ago

What are all the expressions that are equal to 16x-12-24x+4

Sedaia [141]

Answer:

-8x-8

Step-by-step explanation:

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Translate to an inequality using the variable x. A number is less than 2​, or greater than 6 and less than or equal to 9.

Translate to an inequality using the variable x. A number is less than 2, or greater than 6 and less than or equal to 9.