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2 years ago

10

Luke has 75 Vbucks in his account he spends 5 Vbucks every 2 hours. At this rate how many hours did it take for all 75 V bucks t

o be drained from his account?

1 answer:

mel-nik [20]2 years ago

7 0

Answer:

30

Step-by-step explanation:

i did the math lol

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Which is not a step in finding the scale factor of dilation

mariarad [96]

1)To find a Scale factor of Dilation, about the origin

We have

Pre-mage Image

(x, y) k(x,y)

For example

Pre-image Image

(2,4) 2(2,4) = (4,8)

2)When it's not about the origin then we have to count from the Projection Point

Having said this, ex

Which is not a step

a)

We can divide the x value of the image over the pre-image, not the way around.

In the example, I've given if we divide the pre-image over the image value we would have found a scale factor of 1/2. In the example, The scale factor was the inverse: 2

5 0

1 year ago

Let φ(x, y) = arctan (y/x) .

Alexandra [31]

Answer:

a) $\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})$

b) $\large \mathbb{R}^2-\{(0,0)\}$

c) the points of the form (x, -x) for x≠0

Step-by-step explanation:

a)

If φ(x, y) = arctan (y/x), the vector field F = ∇φ would be

$\large F(x,y)=(\frac{\partial \phi}{\partial x},\frac{\partial \phi}{\partial y})$

On one hand we have,

$\large \frac{\partial \phi}{\partial x}=\frac{\partial arctan(y/x)}{\partial x}=\frac{-y/x^2}{1+(y/x)^2}=-\frac{y/x^2}{1+y^2/x^2}=\\\\=-\frac{y/x^2}{(x^2+y^2)/x^2}=-\frac{y}{x^2+y^2}$

On the other hand,

$\large \frac{\partial \phi}{\partial y}=\frac{\partial arctan(y/x)}{\partial y}=\frac{1/x}{1+(y/x)^2}=\frac{1/x}{1+y^2/x^2}=\\\\=\frac{1/x}{(x^2+y^2)/x^2}=\frac{x}{x^2+y^2}$

So

$\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})$

b)

The domain of definition of F is

$\large \mathbb{R}^2-\{(0,0)\}$

i.e., all the plane X-Y except the (0,0)

c)

Here we want to find all the points such that

$\large (-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})=(k,k)$

where k is a real number other than 0.

But this means

$\large -\frac{y}{x^2+y^2}=\frac{x}{x^2+y^2}\Rightarrow y=-x$

So, all the points in the line y = -x except (0,0) are parallel to the vector field F, that is, the points (x, -x) with x≠ 0

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=4%5E%7B2%7D" id="TexFormula1" title="4^{2}" alt="4^{2}" align="absmiddle" class="latex-formula

Komok [63]

Step-by-step explanation:

step 1. what is 4^2?

step 2. 16.

3 0

3 years ago

PLEASE HELP THESE ARE MULTI STEP EQUATIONS!!!!!!!!!

dusya [7]

Answer:

1.-3

2.4

3.3

4. -4

5. -4

6.3

7. -19/9

8. -3

9.0

10. -2

Step-by-step explanation:

7 0

2 years ago

Solve 4X^2+7 = 8X +4 by using the quadratic formula

Sergio [31]

Answer:

(1.5,0)

(.5,0)

Step-by-step explanation:

Quadratic formula below

We first need to move everything to one side of the equation

4x²-8x+3=0

Then plug everything in

(8±√(-8²-4*4*3))/(2*4)

(8±√16)/8

To calculate the ± we need to do when where it's adding and then negative

we have

(8+4)/8=3/2

and hten

(8-4)/8=1/2

4 0

3 years ago