Answer:Your left hand side evaluates to:
m+(−1)mn+(−1)m+(−1)mnp
and your right hand side evaluates to:
m+(−1)mn+(−1)m+np
After eliminating the common terms:
m+(−1)mn from both sides, we are left with showing:
(−1)m+(−1)mnp=(−1)m+np
If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:
(−1)(−1)mn=(−1)n.
It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:
(−1)(−1)mn=(−1)−n=1(−1)n
Multiplying both sides by (−1)n then yields:
1=(−1)2n=[(−1)n]2 which is always true, no matter what n is
Car A consumes 25 gallon and car B consumes 15 gallon.
Step-by-step explanation:
Given,
The fuel efficiency of car A = 20 miles per gallon.
The fuel efficiency of car B = 15 miles per gallon.
In a week, two cars went 725 miles and consumed 40 gallons.
To find the consumption of each car in that week.
Let,
Car A consumed x gallon
Car B consumed y gallon.
According to the problem,
x+y = 40 ----- (1)
20x+15y = 725
or, 4x+3y = 145 -------- (2)
From (1) we get, x = 40-y
Putting the value of x in (2) we get,
4(40-y)+3y = 145
or, 160-4y+3y = 145
or, -y = 145-160
or, y = 15
From (1) we get, x = 40-15 = 25
Hence,
Car A consumes 25 gallon and car B consumes 15 gallon.
4 x (n + 20), pretty simple. :)
F(x)=0
f(x)=y
so where y=0, the x value is the x in f(x)
basically, where the line crosses or touches the x axis, those ar the x values that make the function true
No it does not affect the sum because they have the same sign so it wouldn't make a difference
