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Usimov [2.4K]
3 years ago
10

Help me with this question please ​

Mathematics
1 answer:
emmainna [20.7K]3 years ago
4 0

Answer:

the answer is 27

Step-by-step explanation:

You might be interested in
Given that(4,6) is on the graph of f(x) find the corresponding point for the function f(-4x)
Len [333]

Answer:

(-1,6)

Step-by-step explanation:

Given that(4,6) is on the graph of f(x)

f(-4x) means x is multiplied by -4

When x is multiplied by -1  then there will be reflection over y axis

We multiply every point by -1. so multiply the x values of the given point (4,6) by -1

New point is (-4,6)

If any number is multiplied with x then there will be a horizontal compression or stretch.

4 is multiplied with x , so there will be horizontal compression because 4 is greater than 1

To get new point, we divide the x values by 4 for compression

we already got (-4,6) after multiplying by -1

Now we divide the x coordinate -4 by 4 = -1

So corresponding point for the function f(-4x) is (-1,6)


5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2
Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

but the integrand is even, so this is really just

\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

Substitute x = 1/2 arccot(u/2), which transforms the integral to

\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

7 0
2 years ago
Help me plz u will make my day
iris [78.8K]

Answer:

K=13

Step-by-step explanation:

So first, we subtract 13 with 3/4 (That comes from 4 3/4) and we get 12 1/4.

And then, we subtract 12 1/4 with 4, and we get 8 1/4

Have I made your day?

4 0
3 years ago
Help me with my math homework please.
MariettaO [177]

Answer:

look around the bottom of the page and if it has something like a brand or company whatever write it down in the search and then write the title of the paper and look for pdfs

5 0
3 years ago
An open box is to be made from a six inch by six inch piece of material by cutting equal squares from the corners and turning up
Virty [35]

Answer:

8 inch³

Step-by-step explanation:

Side should be 2 inch

Volume = side³ = 2³ = 8 inch³

4 0
3 years ago
Read 2 more answers
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