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solniwko [45]
3 years ago
8

If the frequency of two alleles in a gene pool is 90%A and 10% a, what is the frequency of individuals in the population with th

e genotype Aa? Use the Hardy-Weinberg Equilibrium.
Mathematics
1 answer:
Sladkaya [172]3 years ago
7 0

Answer: 0.18

Step-by-step explanation:

From the question we know that p = 0.9 and q = 0.1. From this, We can compute the heterozygotes: 2pq = 2 (0.9) (0.1) = 0.18.

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Mlin
antiseptic1488 [7]

Answer:

y-5 = 3/2(x-3)

Step-by-step explanation:

The point slope form of the equation of a line is

y-y1 = m(x-x1)  where m is the slope and (x1,y1) is a point on the line

y-5 = 3/2(x-3)

7 0
3 years ago
Complete the inequality statement.<br><br> 8 ___ 8<br><br> &gt;<br> &lt;<br> =
murzikaleks [220]

Answer:

8 = 8

Step-by-step explanation:

If the numbers are the same, they are equal ( = )

7 0
3 years ago
The parabola opens upward has x = 2 as an axis of symmetry and contains the non -vertex points (1, 9) and (4, 27) write the equa
Sedaia [141]

Answer:

<h3>               f(x) = 6(x - 2)² + 3</h3>

Step-by-step explanation:

f(x) = a(x - h)² + k    - vertex form of the equation of the parabola with vertex (h, k)

"the parabola opens upward" means:  a>0

"the parabola has x = 2 as an axis of symmetry" means:  h = 2

so f(x) = a(x - 2)² + k

"the parabola contains the point (1, 9)" means:

9 = a(1 - 2)² + k

9 = a(-1)² + k

9 = a + k

k = 9 - a

"the parabola contains the point (4, 27)" means:

27 = a(4 - 2)² + k

so:

27 = a(2)² + 9 - a

27 = 4a + 9 - a

3a = 18

a = 6

and  k = 9 - 6 = 3

Therefore the vertex form for this parabola is:

                                     <u> f(x) = 6(x - 2)² + 3</u>

4 0
3 years ago
What is the average (arithmetic mean) of eleven consecutive integers? (1) the average of the first nine integers is 7. (2) the a
laiz [17]

Since eleven is odd, there must be a centra element, which in this case is the sixth. So, we can write 11 consecutive integers as

x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5

Since the arithmetic mean is the sum of the values, divided by how many they are, we have

M = \dfrac{x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5}{11} = \dfrac{11x}{11} = x

So, the mean of 11 consecutive integers is the 6th integer.

4 0
3 years ago
Where did Jordan make her mistake? GIVING BRAINLIEST!
Ivenika [448]

Answer:

Jordan made mistake in his first step while multiplying.

Step-by-step explanation:

Given expression of Jordan's work is

14(8+4x) = 6x-(5-11x)

In the first step, Jordan multiplied the numbers to remove the braces.

He multiplied 14(8+4x) wrong as 14*8 is 112 rather than 126and on the right hand side, he did not change the sign of 11x to positive as two negatives are positive when multiplied.

Hence,

Jordan made mistake in his first step while multiplying.

7 0
3 years ago
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