The answer is 4,16,64 because your squaring each one hope this helps :)
All reals is the answer.
Since y =-9 graph is way below the absolute value graph. Meaning that y value of modulus is greater than the constant graph.
<h2>94.2 cm (pi rounded to 3.14)</h2><h3>15 x 2 = 30</h3><h3>30 x 3.14 = 94.2</h3>
Answer:
The value in box of circle B is 3 and the value in box which belongs in both circle B and S is 6 and value which belongs in circle S is 1 and the value of box outside both the circle is 2.
Step-by-step explanation:
In given Venn diagram
ε = class of 12 pupils
pupils who have brother B = 9
pupils who have sister S = 7
pupils who have neither brother nor sister = 2
Hence the Venn diagram is drawn in the attachment for your reference.
n(E) =12
n(neither B nor S) = 2
So, n(B or S)= n(E) - n(neither B nor S)= 12-2=10
n(B) = 9
n(S) = 7
Now, addition theorem,
n(B or S) = n(B) + n(S) - n(B and S)
![10=9+7-n(B\ and \ S)\\n(B\ and \ S) = 6](https://tex.z-dn.net/?f=10%3D9%2B7-n%28B%5C%20and%20%5C%20S%29%5C%5Cn%28B%5C%20and%20%5C%20S%29%20%3D%206)
So the value in box which is in both circle B and S is 6.
So the Box which contains only brothers = n(B) - n(B and S) = 9 - 6 = 3
Value in box of circle B is 3.
So the Box which contains only Sisters = n(S) - n(B and S) = 7 - 6 = 1
Value in box of circle S is 1.
When you see the subtraction<span> (</span>minus<span>) sign followed by a </span>negative<span> sign, turn the two signs into a plus sign. Thus, instead of </span>subtracting<span> a </span>negative<span>, you're adding a </span>positive<span>, so you have a simple addition problem.</span>