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3 years ago

What is 9/10-(BLANK)=1/5????????? HEEEEEEEELLLLLPPP MEEEEEEE

Mathematics

2 answers:

Bess [88]3 years ago

8 0

Answer:

Step-by-step explanation:

7/10

elixir [45]3 years ago

5 0

Answer:

7/10

Step-by-step explanation:

9/10-x=1/5

1/5=2/10

9/10-x=2/10

7/10-x=0

x=7/10

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Helpppppppppppppppppppppppp

nexus9112 [7]

Answer: You divide the top row by itself and you multiply the top by 2 each time.

Step-by-step explanation: Multiply 72 by 2 each time on top and the bottom row just simply add 1.

Sorry if it is wrong but i hope it helps!

8 0

3 years ago

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper

Korvikt [17]

Answer:

90.67% probability that John finds less than 7 golden sheets of paper

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it contains a golden sheet of paper, or it does not. The probability of a container containing a golden sheet of paper is independent of other containers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper containers.

This means that $p = 0.3$

14 of these containers of paper.

This means that $n = 14$

What is the probability that John finds less than 7 golden sheets of paper?

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{14,0}.(0.3)^{0}.(0.7)^{14} = 0.0068$

$P(X = 1) = C_{14,1}.(0.3)^{1}.(0.7)^{13} = 0.0407$

$P(X = 2) = C_{14,2}.(0.3)^{2}.(0.7)^{12} = 0.1134$

$P(X = 3) = C_{14,3}.(0.3)^{3}.(0.7)^{11} = 0.1943$

$P(X = 4) = C_{14,4}.(0.3)^{4}.(0.7)^{10} = 0.2290$

$P(X = 5) = C_{14,5}.(0.3)^{5}.(0.7)^{9} = 0.1963$

$P(X = 6) = C_{14,6}.(0.3)^{6}.(0.7)^{8} = 0.1262$

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0068 + 0.0407 + 0.1134 + 0.1943 + 0.2290 + 0.1963 + 0.1262 = 0.9067$

90.67% probability that John finds less than 7 golden sheets of paper

7 0

2 years ago

What is the answer to -6-(-2)=

Irina-Kira [14]

Answer:

-4

explanation:

since there is subtraction sign in front of the negative 2 it would change into a positive 2.

-6 + 2 = -4

8 0

2 years ago

Read 2 more answers

It takes Earth about 365 days to orbit the Sun. It takes Uranus about 85 times as long. Write a numerical expression to describe

steposvetlana [31]

U=days of Uranus Orbit
365x85=U

3 0

3 years ago

) Evaluating a polynomial limit analytically You should have learned by now the process for finding the derivative of a polynomi

wolverine [178]

Answer:

This code or is program to find a given value of derivative of a polynomial.

Step-by-step explanation:

We know already how to apply or make the procedures mathematically talking so this short program will eventually help you how to find logic.

// libraries

#include <stdio.h>

#include <conio.h>

//use to control floating elements

float poly(float a[], int, float);

//main

int main()

{

// Enter the degree of polynomial equation

float x, a[10], y1;

int deg, i;

printf("Enter the degree of polynomial equation: ");

scanf("%d", &deg);

printf("Ehter the value of x for which the equation is to be evaluated: ");

// Enter the coefficient of x to the power

scanf("%f", &x);

for(i=0; i<=deg; i++)

{

printf("Enter the coefficient of x to the power %d: ",i);

scanf("%f",&a[i]);

}

// The value of polynomial equation for the value of x

y1 = poly(a, deg, x);

printf("The value of polynomial equation for the value of x = %.2f is: %.2f",x,y1);

return 0;

}

/* function for finding the value of polynomial at some value of x */

float poly(float a[], int deg, float x)

{

float p;

int i;

p = a[deg];

for(i=deg;i>=1;i--)

{

p = (a[i-1] + x*p);

}

return p;

}

8 0

2 years ago