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Agata [3.3K]
4 years ago
10

What is 9/10-(BLANK)=1/5????????? HEEEEEEEELLLLLPPP MEEEEEEE

Mathematics
2 answers:
Bess [88]4 years ago
8 0

Answer:


Step-by-step explanation:

7/10

elixir [45]4 years ago
5 0

Answer:

7/10

Step-by-step explanation:

9/10-x=1/5

1/5=2/10

9/10-x=2/10

7/10-x=0

x=7/10

You might be interested in
14. The area of a rectangle is 375 square inches and it’s perimeter is 80 inches. Find both the length and width.
Pavel [41]

Answer:

Length  =25 inches

Width = 15 inches

Step-by-step explanation:

Let l = length of rectangle, w = width of rectangle

Given the area and the perimeter of the rectangle, we can write:

lw = 375

2l+2w=80

So:

l+w = 80\div2

=40

l=40-w

Now, we can use substitution to find the value of w:

lw = 375

(40-w)w = 375

40w-w^2 = 375

375+w^2-40w = 0 (Quadratic equation)

(w-15)(w-25) = 0

∴ w = 15, 25

We can use substitution again to find the value of l

lw = 375

l=375\div w

=25,15

∵ Length usually refers to the longer side of a rectangle, ∴ length =25 inches and width =15 inches.

Hope this helps :)

8 0
3 years ago
If anyone can help me answer this it would be great thx
zzz [600]
Ok so remember
area=pir^2
area=256pi

256pi=pir^2
divide both sides by pi
256=r^2
squaer root
16=r

find r and d
d=2r
d=2(16)
d=32

radius=16ft
diameter=32ft




6 0
3 years ago
Read 2 more answers
A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6
galina1969 [7]
<h2>Hello!</h2>

The answers are:

a) The height of the ball after 3 seconds is 49 feet.

b) The maximum height of the ball is 66 feet.

c) That the ball hit the ground after 4 seconds.

d) The domain would be only the positive real numbers, from 0 to 4, since we found that the ball hit the ground at t equal to 4 seconds. However, if we were talking about a quadratic function with no time involved, the domain would be all the real numbers.

<h2>Why?</h2>

Since we are working with a quadratic function which describes the ball's motion in function of the time, we need to remember the following:

- The general equation of the parabola is:

y=ax^{2} +bx+c

- We can calculate the coordinates of the vertex of the parabola using the following formula:

x_{vertex}=\frac{-b}{2a}

- Evaluating a function means replacing the variable with the given value to evaluate.

The given function is:

h(t)=-16x^{2}+63t+4

Where,

a=-16\\b=63\\c=4

Now, calculating we have:

a) What is the height of the ball after 3 seconds?

We need to evaluate the time of 3 seconds into the function, so:

h(3)=-16(3)^{2} +63(3)+4=49feet

So, the height of the ball after 3 seconds is 49 feet.

b) What is the maximum height of the ball?

Since the function is describing the motion of a ball thrown into the air, we can find the maximum height by finding the y-coordinate of the vertex. If the parabola opens downward or upward, the vertex will be always the highest or the lowest point of the parabola.

So, calculating the vertex we have:

x_{vertex}=\frac{-b}{2a}=\frac{-63}{2*-16}\\\\x_{vertex}=\frac{-63}{2*-16}=\frac{-63}{-32}=1.97

Then, replacing "x" into the equation of the parabola, we find the y-coordinate of the vertex:

y=-16(1.97)^{2}+63(1.97)+4=-16*3.88+63*1.97+4\\y=-16*3.88+63*1.97+4=-62.08+124.11+4=66.03

So, if the y-coordinate is 66.03, the maximum height of the ball is 66.03 feet, or 66 feet (rounded to the nearest foot).

c) When will the ball hit the ground?

We can find the time when the ball hit the ground by making equal to 0 the function and finding the roots (zeroes)

Since it's a quadratic function, we can find the zeroes using the quadratic equation:

\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

Substituting a, b and c, we have:

\frac{-b+-\sqrt{b^{2}-4ac } }{2a}=\frac{-63+-\sqrt{63^{2}-4*(-16)*(4)} }{2*(-16)}\\\\\frac{-63+-\sqrt{63^{2}-4*(-16)*(4)} }{2*(-16)}=\frac{-63+-\sqrt{3969+256} }{-32}\\\\\frac{-63+-\sqrt{3969+256} }{-32}=\frac{-63+-\sqrt{4225} }{-32}=\frac{-63+-(65)}{-32}\\\\t1=\frac{-63-(65)}{-32}=4\\\\t1=\frac{-63+(65)}{-32}=-0.06

Now, since negative time does not exists, we can conclude that the ball hit the ground after 4 seconds.

d) what domain makes sense for the function?

Since the function represents the motion of the thrown ball at "t" time, the domain would be only the positive real numbers, from 0 to 4, since we found that the ball hit the ground at t equal to 4 seconds. However, if we were talking about a quadratic function with no time involved, the domain would be all the real numbers,

Note: I've attached the graph of the function.

Have a nice day!

5 0
3 years ago
Rotate -4,3 90 degrees counter clockwise
Delicious77 [7]
The answer would be (4,3)

8 0
3 years ago
11. An old machine requires three times as many hours to complete a job as
valentinak56 [21]

Answer:

Step-by-step explanation:

9(r_n+r_o)=1\\ \\ r_n+r_o=\frac{1}{9}\\ \\ r_o=\frac{r_n}{3}\\ \\ r_n+\frac{r_n}{3}=\frac{1}{9}\\ \\ \frac{4r}{3}=\frac{1}{9}\\ \\ 4r=\frac{1}{3}\\ \\ r=\frac{1}{12}\\ \\ \text{So working alone it would take the new machine 12 hours to finish the job.}

8 0
3 years ago
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