Answer:
The electric field produced by this disk along the x axis at point (P = 1.01 m, 0.00 m) is 996.54 N/C
Explanation:
The electric field produced by this disk along the x axis at point (P = 1.01 m, 0.00 m), will be evaluated as follows:
Since x > 0
σ is surface charge density = 5.88 × 10⁻⁶ C / m²
R is the radius = 7.52cm = 0.0752m
position x = 1.01m
k is coulomb force constant = 8.99 × 10⁹ Nm² / C²
= 996.54 N/C
Therefore, The electric field produced by this disk along the x axis at point (P = 1.01 m, 0.00 m) is 996.54 N/C
Mass of 25 kg weight is 25/9.81 slug of mass.
Let F = required force, N
Given:
d = 12 m, distance
W = 280 J, work done
By definition,
W = F*d,
therefore
(F N)*(12 m) = (280 J)
F = 280/12 = 23.33 N
Answer: The force is 23.3 N (nearest tenth)
The constant in Newton's law of gravitation relating gravity to the masses and separation of particles, equal to 6.67 × 10-11N m2 kg-2.