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Elena-2011 [213]
3 years ago
15

True Or False;

Physics
1 answer:
tino4ka555 [31]3 years ago
3 0
False: because atoms are base on the elements on the periodic table.
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A carbon resistor is to be used as a thermometer. On a winter day when the temperature is 4.00°C, the resistance of the carbon r
dusya [7]

Answer:

28 degree C

Explanation:

We are given that

T_1=4.00^{\circ}

R_1=217.7 \Ohm

R_2=215.1\Ohm

\alpha=-5.00\times 10^{-4}C^{-1}

We have to find the temperature on a spring day when resistance is 215.1 ohm.

We know that

\alpha(T_2-T_1)=\frac{R_2}{R_2}-1

Using the formula

-5.00\times 10^{-4}(T_2-4)=\frac{215.1}{217.7}-1

-5\times 10^{-4}(T_2-4)=0.988-1=-0.012

T_2-4=\frac{0.012}{5\times 10^{-4}}=24

T_2=24+4=28^{\circ}C

Hence, the temperature  on a spring day 28 degree C.

7 0
3 years ago
2. A car traveling 300 miles in 5 hours is an example of
Tom [10]
The answer would be a speed
5 0
2 years ago
in vision, the ____ stream controls identification of an object, and the ____ stream controls action toward the object.
prisoha [69]

Answer: In vision, the ventral stream controls identification of an object, and the dorsal stream controls action toward the object.

Explanation: The ventral stream is associated with object recognition and form representation.

Dorsal stream  a pathway that carries visual information from the primary visual cortex to the parietal lobe.

Hope it helps :)

7 0
2 years ago
You stop for a cappuccino at a coffee shop and notice that the tiny white bubbles of steamed milk remain on the surface of the c
Rom4ik [11]

Answer:

C. less dense than the coffee but more dense than the air above thecoffee.

Explanation:

3 0
3 years ago
A cannon can make a maximum angle of 30 degrees with the horizon. What is the minimum speed of a cannon ball if it must clear a
stiks02 [169]

Answer:

28.3 m/s

Explanation:

From the question given above, the following data were obtained:

Angle of projection (θ) = 30°

Maximum height (H) = 10 m

Acceleration due to gravity (g) = 10 m/s²

Initial velocity (u) =?

Thus, we can obtain the minimum velocity cannon ball by using the following formula:

H = u²Sine² θ / 2g

10 = u² × (Sine 30)² / 2× 10

10 = u² × (0.5)² / 20

10 = u² × 0.25 / 20

10 = u² × 0.0125

Divide both side by 0.0125

u² = 10/ 0.0125

u² = 800

Take the square root of both side

u = √800

u = 28.3 m/s

Therefore, the minimum speed of the cannon ball is 28.3 m/s

8 0
3 years ago
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