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PtichkaEL [24]
4 years ago
12

Based on your knowledge of the electromagnetic spectrum, why are radio waves considered harmless while ultraviolet waves and x-r

ays considered harmful?
A) Radio waves have longer wavelengths, lower frequency, and lower energy than ultraviolet waves and x-rays.
B) Lower energy and higher frequency ultraviolet waves and x-rays is enough to break bonds and damage cells.
C) High frequency and energy of radio waves mean that they penetrate much farther through matter than uv or x-rays.
D) The energy of the lower frequency ultraviolet waves and x-rays is high enough to be considered ionizing radiation.
Physics
2 answers:
svlad2 [7]4 years ago
7 0
This is a very poorly written question.  The more you try to
discuss it, the more confusing and misleading it becomes.

The answer it's fishing for is 'A', and I think I'll leave it right there.
Goryan [66]4 years ago
4 0

The correct answer of this question is : A) Radio waves have longer wavelengths, lower frequency, and lower energy than ultraviolet waves and x-rays.

EXPLANATION :

Before going to answer this question, first we have to know the electromagnetic spectrum.

Electromagnetic spectrum is the arrangement of electromagnetic waves in the ascending order of frequency or descending order of wavelength.

When the waves are arranged in the ascending order of their frequency, then perfect order is given below as such -

Radio wave < Micro wave <  Infrared wave <   Visible light < U.V ray<  X-ray < Gamma ray .

Hence, we see that radio wave has the least frequency, and gamma ray has the most frequency.

We know that wavelength and frequency are inversely are inversely proportional to each other. Hence, radio wave has more wavelength and less frequency.

The wave having more frequency is more energetic. Hence, gamma is more energetic and radio wave is less energetic .



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Answer:

a)  h'= 5/7 h , b)   h ’= h

Explanation:

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Starting point. Upper left side

         Em₀ = mg h

Final point. Lower left side

        Emf = K = ½ m v² + ½ I w²

        Em₀ = emf

        mgh = ½ m v² + ½ I w²

Angular and linear velocity are related

           v = r w

           w = v / r

The moment of inertia of the marble that we take as a solid sphere is

           I = 2/5 m r²

We substitute

          m g h = ½ m v² + ½ 2/5 m r² (v / r)²

          g h = ½ v2 (1 + 2/5)

         v = √(g h 10/7)

This is the speed at the bottom of the bowl

Now let's apply energy conservation to the right side

a) right side if rubbing

             Em₀ = K

              Emf = U = mg h’

             ½ m v² = mg h’

              h’= ½ (g h 10/7) / g

              h'= 5/7 h

b) right side with rubbing

             Em₀ = K

             Emf = K + U = -½ I w² + m g h

             Emf = -½ 2/5 m r² v² / r² + m gh

            Em₀ = emf

            ½ v² = -1/5 v² + g h’

            h’= (1/2 +1/5) (gh 10/7) / g

            h ’= h

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The driver of a 1750 kg car traveling on a horizontal road at 110 km/h suddenly applies the brakes. Due to a slippery pavement,
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Answer: a=-2.4525 m/s^2

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According to newton second law of motion

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