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Stells [14]
3 years ago
13

What is this expression in simplest form?

ula1" title="(2x^{5})(3x^{3/5})" alt="(2x^{5})(3x^{3/5})" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
JulijaS [17]3 years ago
8 0
Multiply the numbers and add the exponents.
(2*3)(x^(5+3/5))
= 6x^(28/5)
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Suppose you deposited ​$100 in a savings account 2 years ago. The simple interest rate is 2.7%. The interest that you earned in
gladu [14]

Answer:

ok if im right mark me branly pleaseeee

Suppose you deposited $100 in a savings account 4 years ago with a simple interest rate of 2.2%.

Principal P= $ 100

Time t = 4 years

rate of interest = 2.2 %

Formula of simple interest

Plugging the value in formula

simple interest =

simple interest =

simple interest = $ 8.8

so the stament is true

Step-by-step explanation:

4 0
3 years ago
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The volume of a cylinder is 72 7 cm. If the radius is 3 cm, what is the height
Alexxx [7]

Answer:

The answer is B. 8 cm

6 0
3 years ago
A population has mean 187 and standard deviation 32. If a random sample of 64 observations is selected at random from this popul
Zina [86]

Answer:

11.51% probability that the sample average will be less than 182

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 187, \sigma = 32, n = 64, s = \frac{32}{\sqrt{64}} = 4

What is the probability that the sample average will be less than 182

This is the pvalue of Z when X = 182. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{182 - 187}{4}

Z = -1.2

Z = -1.2 has a pvalue of 0.1151

11.51% probability that the sample average will be less than 182

8 0
3 years ago
If in a sample of 355 adult males, we have a mean total cholesterol level of 185 mg, with s = 16. What is the 95% confidence int
sladkih [1.3K]

Answer:

Step-by-step explanation:

We want to determine a 95% confidence interval for the mean total cholesterol level of all males.

Number of sample, n = 355

Mean, u = 185 mg

Standard deviation, s = 16

For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean +/- z ×standard deviation/√n

It becomes

185 +/- 1.96 × 16/√355

= 185 +/- 1.96 × 0.849

= 185 +/- 1.66404

The lower end of the confidence interval is 185 - 1.66404 =183.336

The upper end of the confidence interval is 185 + 1.66404 = 186.66

Therefore, with 95% confidence interval, the mean total cholesterol level of all males is between 183.336 mg and 186.66 mg

5 0
3 years ago
What is S(0,0),T(4,0),U(3,2),V(-1,2)
Delicious77 [7]
IDK! I'M DOING IT FOR THE POINTS! LEL!
8 0
3 years ago
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