Answer:
y=[-4]x+[10]
Step-by-step explanation:
For a line to be perpendicular to another it must have the reverse reciprocal of the opposite line, to find the reverse reciprocal you take your slope, flip the numerator and denominator, and multiply it by -1.
The slope
turns into
and is then multiplied by -1 to become
which can be simplified down to: 
Now that we know the slope we need the line to pass through a point, so we will use point slope form:

Substitute in our slope and point values:

Now solve for y:

Then you will find that line
runs perpendicular to
and intersects point (2,2).
Input is the same as the x-term and output is the same as the y-term.
For example, take a look at the image provided with thee table.
Looking at the first box of our table, notice that if we subtract 5 from 1, we get -4 and if we subtract 5 from 2 we get -3 and if we subtract 5 from 3, we get -2. Notice that in each case, we're subtracting 5 from the input to get the output.
I attached a table so you can practice if you'd like to. All you have to do is subtract 5 from each input and you will end up with the output. The first few are done for you. I also provided an answer key in the next image so you can check your work.
The last one might be a little trick. In the input, we have n which is a variable that represents any number. If we want to find the nth term, we simply subtract 5. So we have n - 5.
First image is practice if you'd like and the second is the key.
If you don't want to do it, no worries.
Answer:
Step-by-step explanation:
We have to remind one of the properties of the limits:
Lim x→a f(x)*g(x) = [Lim x→a f(x)]*[Lim x→a g(x)]
Hence, we evaluate the products of the limits
(a) Lim x→a f(x)*g(x) = 0*0 = 0
(b) Lim x→a f(x)*p(x) = 0*[infinity] = INDETERMINATE
(c) Lim x→a h(x)*p(x) = 1*[infinity] = infinity
(d) Lim x→a p(x)*q(x) = [infinity]*[infinity] = INDETERMINATE
Answer:
If m= 32 then the answer is 320
If you're looking to find m then the answer is m= -10
Step-by-step explanation:
(2 + 8)32
(10)32
320
(2+8)m
set it equal to 0
(2+8)m=0
(10)m=0
-10
m= -10