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adelina 88 [10]
4 years ago
14

If an object is projected upward with an initial velocity of 124124 ft per​ sec, its height h after t seconds is h equals negati

ve 16 t squared plus 124 th=−16t2+124t. Find the height of the object after 44 seconds.
Mathematics
1 answer:
Valentin [98]4 years ago
8 0
The object goes up, reaches its maximum height, goes down, and hits the ground 7.75 seconds after being projected. If nobody steals it, it's still there when t=44 sec.
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