Answer:
C. (-3,11)
Step-by-step explanation:
Tp is (-3,6) implies the quadratic could have been
f(x) = (x+3)²+6
(2/3)f(x) = (2/3)[(x+3)²+6]
= (2/3)(x+3)²+4
(2/3)f(x)+3 = (2/3)(x+3)²+4+3
= (2/3)(x+3)²+7
Tp at (-3,7)
Alternately,
No change in domain so x remains-3
(2/3)f(x) changes y from 6 to 4 (6×2/3)
+3 increases the y by 3
i.e 4+3 = 7
So, (-3,7)
<span>First of all in order to find the exact value by using a half angle identity we will do
cos(5π divided by 12)
=cos (5π divided by 6) divided by 2
= ± Under root[(1+cos (5π divided by 6) divided by 2]
Now we will consider + sign because 5π divided by 12 is in quadrant. where cos>0
so the solution is [(1- Under root 3 divided by 2) divided by 2]
We will ignore the negative sign
I hope it helped.</span>
The answer is three and twelve
You keep adding 2 and 1/3 to get your answer
