How do you get the answer for 7 5/6 + 2 3/6

2 answers:

4 0

First you convert 7 5/6 to a improper fraction which will be 47/6 Then you convert 2 3/6 (2 1/2) into a improper fraction which will be 15/6 Finally you add the fractions together. 47+15=62/6 Then you change that into a mixed number which is 10 2/6 or 10 1/3

ANSWER: 10 2/6 or 10 1/3

Blizzard [7]3 years ago

3 0

First you would add 5/6 and 3/6 which would be 8/6. Next you would convert the improper fraction (8/6) into a mixed number which would be 1 2/6. Now just add 7 and 2 which is 9. Finally you would add the whole number and the mixed number. So your answer is 10 2/6 unless the instructions say to simplify then your answer would be 10 1/3.

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Keith_Richards [23]

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$n^2\equiv k\mod8,k\in\{0,1,4\}$

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Let's consider some sub-cases.

Suppose $n=2\ell-1$ is odd. Then

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If $\ell$ is even, then so is $\ell^2-\ell$ , which means you can write $4\ell^2-4\ell=8m$ for some integer $m$ , and this reduces to $n^2\equiv1\mod8$ .

If $\ell$ is odd, the same thing happens; you get that $\ell^2-\ell$ is still even, so $4\ell^2-4\ell\equiv0\mod8$ and you're left again with $n^2\equiv1\mod8$ .

Now assume $n=2\ell$ is even. Then $n^2=4\ell^2$ . If $\ell=2j$ is even, then you will always be able to write

$n^2=(2\ell)^2=4\ell^2=4(2j)^2=8\times2j^2\equiv0\mod8$

Meanwhile, if $\ell=2j-1$ is odd, then

$n^2=4\ell^2=4(2j-1)^2=16j^2-16j+4\equiv4\mod8$

So you conclude that

$n^2\equiv\begin{cases}0\mod8&\text{for }n\in\{4,8,12,16,\ldots\}\\1\mod8&\text{for }n\in\{1,3,5,7,\ldots\}\\4\mod8&\text{for }n\in\{2,6,10,14,\ldots\}\end{cases}$

5 0

3 years ago

A painter places an 11-ft ladder against a house. The base of the ladder is 3 ft from the house. How high on the house does the

Paha777 [63]

Use Pythagoras theorem
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4 0

3 years ago

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kakasveta [241]

<u>Solution-</u>

From the figure,

AE = 2.4

EB = 2.8

BC = 11.7

Area of rectangle 1 = 8.68 sq.in

$\Rightarrow FH \times HI=8.68$