Hellllllllllllllllllp...

Mathematics

1 answer:

Anastasy [175]3 years ago

4 0

Given:

The expression is:

$\dfrac{15m^2-3}{3m-1}$

To find:

The simplified value of the given expression.

Solution:

We have,

$\dfrac{15m^2-3}{3m-1}$

On dividing, we get

$(3m-1)|\overline{15m^2+0m-3}|5m+\dfrac{5}{3}$

$-(15m^2-5m)$

$\overline{\quad \quad -5m-3}$

$-(5m-\dfrac{5}{3})$

$\overline{\quad \quad -\dfrac{4}{3}}$

Here, quotient is $5m+\dfrac{5}{3}$ and the remainder is $-\dfrac{4}{3}$ .

Therefore, $\dfrac{15m^2-3}{3m-1}=5m+\dfrac{5}{3}-\dfrac{4}{3(3m-1)}$ .

You might be interested in

The table shows the height of a soccer ball that has been kicked from the ground over time. (For reference: h(t) = 144 – 16t2) T

natta225 [31]

The answer is:

The rate of change is not constant and increases then decreases over time. The height of the ball above ground gets larger until 1.25 seconds and then gets smaller after that time.

Here's how:

The rate of change of the function is defined and calculated as (refer to the statement beloew):

r = [change in height] / {change in time]

For the Table:

refer to the attached picture.

The table shows the calculations for the rate of change (r) for each interval given.

And for the Conclusion,

Refer to the table and notice that in the third ans fifth columns show that:

The rate of change is not constant and increases then decreases over time. The height of the ball above ground gets larger until 1.25 seconds and then gets smaller after that time.