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Vesnalui [34]
3 years ago
14

A diver descends to a location of -50 1 over 4 meters relative to the surface of the water. He then descends another 10 1 over 2

meters. What is the diver's final location relative to the surface of the water? Enter your answer as a simplified mixed number in the box

Mathematics
2 answers:
liubo4ka [24]3 years ago
8 0

Answer:

The correct answer is -60  3/4

Step-by-step explanation:

Yanka [14]3 years ago
3 0

Answer:

-60\frac{3}{4} meters.

Step-by-step explanation:

To find diver's final location relative to the surface of water we will subtract  10\frac{1}{2} from -50\frac{1}{4} because diver dives away another 10\frac{1}{2} from his previous location of -50\frac{1}{4}.

-50\frac{1}{4} -10\frac{1}{2}

Now we will convert our mixed fraction into improper fraction and then we will find a common denominator.

\frac{-201}{4} -\frac{21}{2} =\frac{-201-42}{4}

=\frac{-243}{4}

Now let us convert our answer in mixed fraction.

=\frac{-243}{4}=[tex]-60\frac{3}{4}[/tex]

Therefore, diver's final location relative to the surface of the water is -60\frac{3}{4} meters.

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