Question

A diver descends to a location of -50 1 over 4 meters relative to the surface of the water. He then descends another 10 1 over 2 meters. What is the diver's final location relative to the surface of the water? Enter your answer as a simplified mixed number in the box

Answer 1

Answer:

The correct answer is -60  3/4

Step-by-step explanation:

Answer 2

Answer:

$-60\frac{3}{4}$ meters.

Step-by-step explanation:

To find diver's final location relative to the surface of water we will subtract  $10\frac{1}{2}$ from $-50\frac{1}{4}$ because diver dives away another $10\frac{1}{2}$ from his previous location of $-50\frac{1}{4}$.

$-50\frac{1}{4} -10\frac{1}{2}$

Now we will convert our mixed fraction into improper fraction and then we will find a common denominator.

$\frac{-201}{4} -\frac{21}{2} =\frac{-201-42}{4}$

$=\frac{-243}{4}$

Now let us convert our answer in mixed fraction.

$=\frac{-243}{4}=[tex]-60\frac{3}{4}$[/tex]

Therefore, diver's final location relative to the surface of the water is $-60\frac{3}{4}$ meters.