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tekilochka [14]
3 years ago
14

Use Cramer’s rule to solve for x: x + 4y − z = −14 5x + 6y + 3z = 4 −2x + 7y + 2z = −17

Mathematics
2 answers:
nata0808 [166]3 years ago
8 0

Answer:

Solve using determinants:

x + 4y − z = −14  

5x + 6y + 3z = 4  

−2x + 7y + 2z = −17  

|A| =  -120  

|Ax| =  -240

|Ay| = 360  

|Az| = -480  

x =  2

y = -3    

z =  4

Step-by-step explanation:

Solving a 3 x 3 Linear System Using Cramer's Rule

sweet-ann [11.9K]3 years ago
7 0

Answer:

A = -120

AX = -240

X = 2

Step-by-step explanation:

∵ x + 4y - z = -14

∵ 5x + 6y + 3z = 4

∵ -2x + 7y + 2z = -17

\left[\begin{array}{ccc}1&4&-1\\5&6&3\\-2&7&2\end{array}\right]=\left[\begin{array}{ccc}-14\\4\\-17\end{array}\right]

∴ A = 1(6×2 - 3×7) + (-4)(2×5 - 3×-2) + (-1)(5×7 - 6×-2)

∴ A = 1(12 - 21) + (-4)(10 - -6) + (-1)(35 - -12)

∴ A = -9 + (-4)(16) + (-1)(47) = -9 - 64 - 47 = -120

To find X replace the column of X by the column of the answer

\left[\begin{array}{ccc}-14&4&-1\\4&6&3\\-17&7&2\end{array}\right]

∴ AX = -14(6×2 - 3×7) + (-4)(4×2 - 3×-17) + (-1)(4×7 - 6×-17)

∴ AX = -14(12 - 21) + (-4)(8 - -51) + (-1)(28 - -102)

∴ AX = 126 + (-4)(59) + (-1)(130) = 126 - 236 - 130 = -240

∴ X = AX/A = -240/-120 = 2

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X-y+4z=5<br> 4x+z=2<br> x+5y+z=17
JulsSmile [24]

Answer:x = 0, y = 3, z = 2

Step-by-step explanation:

The given system of equations is expressed as

x - y + 4z = 5 - - - - - - - - - - - - - -1

4x + z = 2

z = 2 - 4x- - - - - - - - - - - - - -2

x + 5y + z = 17- - - - - - - - - - - - - -3

From equation

Substituting equation 2 into equation 1 and equation 3, it becomes

x - y + 4(2 - 4x) = 5

x - y + 8 - 16x = 5

x - 16x - y = 5 - 8

- 15x - y = - 3 - - - - - - - - - - - - - -4

x + 5y + 2 - 4x = 17

x - 4x + 5y = 17 - 2

- 3x + 5y = 15- - - - - - - - - - - - - -5

We would eliminate y by multiplying equation 4 by 5 and equation 5 by 1. It becomes

- 1

- 75x - 5y = - 15

- 3x + 5y = 15

Adding both equations, it becomes

- 78x = 0

x = 0

Substituting x = 0 into equation 2, it becomes

z = 2 - 4 × 0

z = 2

Substituting x = 0 and z = 2 into equation 1, it becomes

0 - y + 4 × 2 = 5

- y + 8 = 5

y = 8 - 5

y = 3

6 0
3 years ago
Simplify the expression\(\frac{2x^{-1}y}{x^3z}\) for \(x=2\), \(y=8\), and \(z=-1\).
adelina 88 [10]

2 <em>x</em> ⁻¹ <em>y</em> / (<em>x</em> ³ <em>z</em>) = 2 <em>y</em> / (<em>x</em> ⁴ <em>z</em>)

… = 2 × 8 / (2⁴ × (-1))

… = 16 / (-16)

… = -1

8 0
3 years ago
Read 2 more answers
Use the Addition Formula for Cosine to prove the Double-Angle Formula for Cosine. cos(2x) = cos2(x) − sin2(x) Rewrite 2x as x +
andre [41]

Answer with Step-by-step explanation:

We are given that

LHS

cos 2x

To prove that

cos 2x=cos^2x-sin^2 x

cos(x+x)

We know that

cos(x+y)=cos xcosy-sinx siny

Using the formula

cos(x+x)=cosx\cdot cosx-sinx\cdot sinx

cos2 x=cos^2 x-sin^2 x

By using

cosx\cdot cosx=cos^2 x

sinx\cdot sinx=sin^2 x

LHS=RHS

Hence, proved.

3 0
3 years ago
The distance between points (X7, Yı) and (4, 8) is the square root of (x7 - 8)2 +
serious [3.7K]

Answer:

B. False

Step-by-step explanation:

Given

Points: (x_7 - y_i),(4,8)

Required

Is the distance between them \sqrt{(x_7 - 8)^2 + (y_1 - 4)^2}

Given that there are two points, the distance between them is calculated using

Distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

In this case;

(x_1,y_1)= (x_7 - y_i)\\(x_2,y_2) =(4,8)

Substitute these in the given formula

Distance = \sqrt{(4- x_7)^2 + (8 - y_1)^2}

Comparing this with the given formula, both are not the same;

Hence, the formula is false and the correct formula is of the form \sqrt{(4- x_7)^2 + (8 - y_1)^2}

6 0
3 years ago
Pls helpppp!!! I will give brainliest.
pashok25 [27]

Answer:

Step-by-step explanation:

The domain represents the x-values

The range represents the y-values

Domain             Range

  3                        7

                            8

                            -2

                             4

                             1

This relation is not a function because the domain value was used more than one time.  

8 0
2 years ago
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