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3 years ago

Which compound sentence has its solution set shown on the graph below?

Mathematics

1 answer:

gogolik [260]3 years ago

3 0

There might be a simpler way to do this, if there is, sorry.

If you look at the graph, x is greater than 3 but less than 5.

So: x > 3 and x < 5

I would simplify each solution set and get "x" by itself (until I get the right answer):

A.) 2x - 4 > 6 or 3x < 9

2x - 4 > 6 Add 4 on both sides

2x > 10 Divide 2 on both sides

x > 5 (you could stop here and go to the next choice since you know this does not match the graph)

3x < 9 Divide 3 on both sides

x < 3

x > 5 and x < 3

B.) 2x - 4 < 6 and 3x > 9

x < 5 and x > 3

Your answer is B or the 2nd option

[C and D would have given a negative number]

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3 years ago

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Selma cannot remember her locker number! She knows that her locker number is prime, and that it is a factor of 435. What are all

tatuchka [14]

Answer:

Possible locker numbers for Selma are: 3, 5 and 29

Step-by-step explanation:

First of all, let us have a look at the definition of a prime number.

A prime number is a number which is divisible either by 1 or the number itself.

No other number divides the prime number other than 1 and the number itself.

Now, let us factorize the given number 435 and let us observe the what all possibilities are there.

$435 = 3\times 145$

Factorizing 145 further:

$435 = 3\times 5\times 29$

No further factors are possible.

Therefore 3, 5 and 29 are the prime factors of 435.

So, the answer is:

Possible locker numbers for Selma are: 3, 5 and 29

3 0

2 years ago

I need help with #39-42, please explain.

shusha [124]

For question 39 & 40, we need to use the below equation to complete the sentence

$l=m\sqrt{n}$

Question 39:

When ' n ' increase, the $\sqrt{n}$ will also increase and that multiplied with constant ' m ', the l will also increase.

Solution for question 39:

As $n$ increases and $m$ stays constant , $l$ increases

-------

Question 40:

Solving the equation for m, we get

$l = m\sqrt{n} \\ \\ m=\frac{l}{\sqrt{n}}$

When ' l ' increases, the numerator increase, the denominator stays constant because 'n' stays constant, for this condition, the fraction increases.

Solution for question 40:

As $l$ increase and $n$ stays constant, $m$ increases

------

For question 41 & 42, we need to use the below equation to complete the sentence

$r=s^2/t^2$

Question 41:

When $s$ is triped, the equation will be...

$r=(3s)^2/t^2=\frac{3^{2}s^{2}}{t^2} =9s^2/t^2$

Solution for question 41:

If $s$ is tripled and $t$ stays constant, $r$ is multiplied by 9

--------

Question 42:

When t is doubled, the equation will be...

$r=s^2/(2t)^2=\frac{s^2}{2^2 \cdot t^2}=\frac{s^2}{4t^2}\\ \\ r=0.25s^2/t^2 \; \; (or) \; \; \frac{1}{4} \cdot \frac{s^2}{t^2}$

Solution for 42:

If $t$ doubled and $s$ stays constant, $r$ is multiplied by 1/4 or 0.25

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3 years ago

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guapka [62]

Answer:

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2 years ago

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mars1129 [50]

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1 year ago