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3 years ago

Find any real solutions for the following equations x3 = - 64

Mathematics

1 answer:

Alex777 [14]3 years ago

8 0

Hello,

x^3+64=0
==>(x+4)(x²-4x+16)=0
==>x=-4 because x²-4x+16 is not factorable in R.

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Concur Technologies Inc is a large expense-management company located in Redmond Washington. The wall street Journal asked Concu

klio [65]

Answer:

Step-by-step explanation:

Hello!

Given the variables

X: daily hotel room rate

Y: amount spent on the entertainment

See second attachment for scatter plot.

The population regression equation is E(Yi)= α + βXi

To estimate the y-intercept and the slope of the regression equation you have to apply the following formulas:

$b= \frac{sum XY-\frac{(sumX)(sumY)}{n} }{sumX^2-\frac{(sumX)^2}{n} }$

a= Y[bar]-bX[bar]

n= 9; ∑X= 945; ∑X²= 103325; ∑Y= 1134 ∑Y²= 148804; ∑XY= 123307

X[bar]= ∑X/n= 945/9= 105

Y[bar]= ∑Y/n= 1134/9= 126

$b= \frac{123307-\frac{945*1134}{9} }{103325-\frac{(945)^2}{9} }= 1.03$

a= 126 - 1.03*105= 17.49

^Y= 17.49 + 1.03Xi

Slope interpretation: The estimated average amount spent on entertainment increases 1.03 every time the daily hotel room rate increases one unit.

If the room rate for Chicago is $128 (X), to predict the mount spent in entertainment (Y) you have replace it in the estimated regression line:

^Y= 17.49 + 1.03Xi= 17.49 + 1.03*128= 149.33

The expected amount spent on entertainment for Chicago is $149.33

I hope this helps!

6 0

3 years ago

What is 25 miles/hours equal to feet/seconds

taurus [48]

1 mile/hour = 5280 feet/(60 x 60) seconds = 1.467 feet/second

25 miles/hour = 1.467 x 25 = 36.67 feet/second.

7 0

3 years ago

Jim writes 10^4 words every day how many words does he writes in 10^3 days?

Alchen [17]

1,000 words

10^4=10,000
10^3=1,000

7 0

3 years ago

Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif

dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

the confidence interval is (0.0338,0.0392)

Step-by-step explanation:

Step:-1

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals $t_{0.01} =2.82$ (from tabulated value).

$The mean value = 0.0365$

$x±t_{0.01} \frac{S}{\sqrt{n-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{22} }$

$0.0365±2.82 \frac{0.0046}{4.690 }$

using calculator

$0.0365±0.00276$

Confidence interval is

$(0.0365-0.00276,0.0365+0.00276)$

$(0.0338,0.0392)$

the mean value is lies between in this confidence interval

(0.0338,0.0392).

Answer:-

using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.

4 0

3 years ago

Math help <3............

Anna007 [38]

1.)18 = 2(4 + x) ||
2.) 18 = 8 + 2x --- Distribute. ||
3.) 10 = 2x --- Isolate the variable by collecting like terms ||
4.) 5 = x

I'd say A. is a good choice.

8 0

3 years ago

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