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2 years ago

What is the solution to 2x -8 = 2(x - 4 ) ? ALSO, explain how you solved it.

1 answer:

7 0

First, you gotta simplify. There’s really nothing to simplify so just take it out of the parenthesis.

2x-8=2x-4

Now turn the -8 into a +8. Add it on each side.

2x=2x+8

Now turn the 2x on the right into a negative. Do the same thing you did with the 8.
Now it’s:

0 = 8

That means there’s no solution.
Hope this helped :)

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10 hours, 30 minutes.

Step-by-step explanation:

Distance ÷ Speed = Time

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2 years ago

2(x-1) ≥ 10 or 3-4x > 15<br> Solve the compound inequality, and show work!

Veseljchak [2.6K]

Answer:

$x\geq 6\text{ or } x$

Step-by-step explanation:

We have the compound inequality:

$2(x-1)\geq10\text{ or } 3-4x>15$

Let's solve each of them individually first:

We have:

$2(x-1)\geq10$

Divide both sides by 2:

$x-1\geq5$

Add 1 to both sides:

$x\geq6$

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$3-4x>15$

Subtract from both sides:

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Divide both sides by -4:

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$x\geq 6\text{ or } x$

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2 years ago

Read 2 more answers

-(x+3) = 2x-6 what is x

Makovka662 [10]

Answer:

x=1

Step-by-step explanation:

So, first you make sure to multiply the parenthesis by the negative so then it would be,

-x-3=2x-6

Then you add the -3 from the right to the other side

so, -x=2x-3

Then you want all the X variables to one side so you subtract the 2x to both sides.

so, -3x=-3

divide both by -3

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2 years ago

If EF bisects CD.CG = 5x - 1, GD = 7x-13, EF = 6x - 4, and GF = 13. find EG.

Iteru [2.4K]

Answer:

EG = 19

Step-by-step explanation:

* Lets explain how to solve the problem

- If a line bisects another line that means the point of intersection

divides the second line into two equal parts

∵ EF bisects CD at G

∴ CG = GD

∵ CG = 5x - 1

∵ GD = 7x - 13

∴ 7x - 13 = 5x - 1

* Lets solve the equation

∵ 7x - 13 = 5x - 1

- Subtract 5x from both sides and add 13 to both sides

∴ 7x - 5x = 13 - 1

∴ 2x = 12

- Divide both sides by 2

∴ x = 6

- Point G divides EF into two parts EG and GF

∴ EF = EG + GF

∵ EF = 6x - 4

- Substitute the value of x to find EF

∵ x = 6

∴ EF = 6(6) - 4 = 36 - 4 = 32

∴ EF = 32

∵ GF = 13

- Substitute the values of EF and GF in the equation of EF

∴ 32 = EG + 13

- Subtract 13 from both sides

∴ 19 = EG

* EG = 19

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3 years ago

Find the area of following rhombuses. Round your answers to the nearest tenth if<br> necessary.

polet [3.4K]

Answer:

$Area =55.4ft^2$

Step-by-step explanation:

Given

The attached rhombus

Required

The area

First, calculate the length of half the vertical diagonal (x).

Length x is represented as the adjacent to 60 degrees

So, we have:

$\tan(60) = \frac{4\sqrt 3}{x}$

Solve for x

$x = \frac{4\sqrt 3}{\tan(60)}$

$\tan(60) = \sqrt 3$

So:

$x = \frac{4\sqrt 3}{\sqrt 3}$

$x = 4$

At this point, we have established that the rhombus is made up 4 triangles of the following dimensions

$Base = 4\sqrt 3$

$Height = 4$

So, the area of the rhombus is 4 times the area of 1 triangle

$Area = 4 * \frac{1}{2} * Base * Height$

$Area = 4 * \frac{1}{2} * 4\sqrt 3 * 4$

$Area =2 * 4\sqrt 3 * 4$

$Area =55.4ft^2$

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3 years ago