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Rom4ik [11]
3 years ago
14

What is the absolute value of -7/4

Mathematics
2 answers:
valina [46]3 years ago
6 0

Answer:

7/4

Step-by-step explanation:

The absolute value of any number is the positive version of that number.

I hope this helps!

Aleonysh [2.5K]3 years ago
5 0
7/4 absolute value is just making it the opposite ((negative or positive))
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Solve each equation. Explain your method.8.88=4.44(x−7)
omeli [17]
  • 8.88=4.44(x−7)

write the equation

  • 8.88 - 4.44=(x−7)

Transfer 4.44 to other side and it's sign changes from positive to negative

  • 4.44=(x−7)

After subtracting we will get result as 4.44

  • (x−7) = 4.44

Arrange the equation as variable always comes at left side.

  • x−7 = 4.44

open brakets

  • x = 4.44 + 7

transfer 7 to other side and it changes from - to + sign

  • x = 11.44
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2 years ago
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The length of a spring varies directly with the mass of an object that is attached to it. When a 30-gram object is attached, the
Yuri [45]
Hi.
your answer is s=3/10m
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3 years ago
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alex container of cranberry juice holds 200 milliters. harrys container holds 7/8 as much juice. how many milliliters of cranber
blondinia [14]
175mm??? Im not entirely sure. 
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3 years ago
The area of the square is 100 square centimeters. What is the area of the circle?
swat32

Answer:

  • Since the question is incomplete, see the figure attached and the explanation below.

Explanation:

Since the figure is missing, I enclose the figure of a square inscribed in a circle.

Since the <em>area of a square</em> is the side length squared, you can determine the side length:

  • Area = (side length)²
  • 100 cm² = (side lenght)²

        side\text{ }length=\sqrt{100cm^2}=10cm

From the side length, you can find the diagonal of the square, which is equal to the diameter of the circle, using the Pythagorean theorem:

  • diagonal² = (10cm)² + (10cm)² = 2 × (10cm)²

         diagonal=\sqrt{2\times (10cm)^2}\\ \\ diagonal=10\sqrt{2} cm

The area of the circle is π (radius)².

  • radius = diameter/2 = diagonal/2

        area= \pi \times (5\sqrt{2}cm)^2=50\pi cm^2

6 0
2 years ago
równanie zmiany prędkość autokaru poruszającego się po prostym odcinku szosy i rozpoczynającego hamowanie od szybkości 20m/s ma
Rasek [7]

Answer:

s = 22.5 m

Step-by-step explanation:

the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.

v (t) = 25 - 5 t

at t = 0 , v = 20 m/s

Let the distance is s.

s =\int v(t) dt\\\\s =\int (25 - 5t)dt\\\\s= 25 t - 2.5 t^2 \\

Let at t = t, the v = 20

So,

20 = 25 - 5 t

t = 1 s

So, s = 25 x 1 - 2.5 x 1 = 22.5 m

3 0
2 years ago
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