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Vitek1552 [10]
3 years ago
8

Please Help ASAP Evaluate (64^1/2)^-2/3

Mathematics
1 answer:
Naya [18.7K]3 years ago
7 0

Answer:

Option A.

Step-by-step explanation:

The given expression is,

[(64)^{-\frac{1}{2}}]^{-\frac{2}{3}}

By solving the given expression,

(64)^{-\frac{1}{2}}=\frac{1}{(64)^{\frac{1}{2}}} [Since a^{-1}=\frac{1}{a}]

           =\frac{1}{\sqrt{64}}

           =\frac{1}{8}

Now the expression will be,

[(64)^{-\frac{1}{2}}]^{-\frac{2}{3}}=(\frac{1}{8})^{-\frac{2}{3}}

                 =8^{\frac{2}{3}}

                 ={(\sqrt[3]{8})^2}

                 = 2²

                 = 4

Therefore, value of the given expression will be 4.

Option (A) will be the answer.

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Answer:

78.  t=8.66yrs

79.  r=23.10%

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Step-by-step explanation:

78. Given the initial deposit is $1,000 and the 8% compounded continuously. The doubling time can be calculated using the formula;

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79.

Given the initial deposit is $1,000 and the r% compounded continuously.

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#We substitute our values in the equation to solve for r:

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80.

Given the initial deposit is $30,000 and the future value is $2,540,689.

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A=Pe^{rt}, \ \ \ r=r, t=40yrs\\\\2540689=30000e^{40r}\\\\\frac{2540689}{30000}=e^{40r}\\\\r=\frac{In \ (2540689/30000)}{40}\\\\\\=0.110975=11.0975\%

Hence, the deposit will grow at a rate of approximately 11.0975%

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