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Setler [38]
3 years ago
6

Calculate the amount of heat absorbed when 70 mL of water is heated from 30°C to 70°C. The specific heat of liquid water is 4.18

4 J/g °C. The density of water is about 1 g/mL. Report your answer in kJ to one decimal place.
Physics
1 answer:
Annette [7]3 years ago
3 0

Answer:

the heat absorbed by water is Q=11715.2 J

Explanation:

the amount of heat absorbed is

Q = m * c * (T - Ti)

where

Q= heat absorbed by water

m = mass f water heated

c = specific heat of water

T= final temperature , Ti= inicial temperature

also we know that the mass is related with the density through

density = mass/volume

d = m / V → m = d * V

replacing m in the heat equation

Q = m * c * (T - Ti) =  d * V * c * (T - Ti)

replacing values

Q = d * V * c * (T - Ti) = 1 g/ml * 70 ml * 4.184 J/g°C * (70°C - 30°C) = 11715.2 J

Note:

we assume

- constant density of the water between 30° and 70°

- constant specific heat of water between 30° and 70°

- the water has no impurities

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A circuit consists of a 171- resistor and a 0.158-H inductor. These two elements are connected in series across a generator that
kotykmax [81]

Answer:

a ) I= 1.635-i0.0021 b) ∅=   -0.074

Explanation:

a) reactive impeadance= 2πfL

                                 =2(3.14)(147)(0.158)

                                 =145.86 Ω

Z= 171+j145.86

I=V/Z

I=278/(171+j145.86)

I= 1.635-i0.0021

b) ∅=inv.tan (-0.0021/1.635)

 ∅=-0.074

 

6 0
3 years ago
A cargo elevator on Earth (where g = 10 m/s2) lifts 3000 kg upwards by 20 m. 720 kJ of electrical energy is used up in the proce
MakcuM [25]

Answer: 83%

Explanation:

Efficiency of the process = work output/work input × 100%

Work input is the energy used up in the process = 720,000Joules

Work output = Force × distance

= (3000×10)× 20

= 600000 Joules

Efficiency= 600000/720000 × 100

= 0.83×100

= 83%

8 0
3 years ago
1. The saw cut that is made at 450-75° angles to the annual rings is called:
ASHA 777 [7]
I think the answer you or looking for is miter saw please tell me if I’m wrong
4 0
3 years ago
Two machines, A and B, each working at a constant rate, can complete a certain task working together in 6 days. In how many days
Vinvika [58]

your question is missing the given conditions, here is the complete question;

Two machines, A and B, each working at a constant rate, can complete a certain task working together in 6 days. In how many days, working alone, can machine A complete the task?

(1) The average time A and B can complete the task working alone is 12.5 days.

(2) It would take machine A 5 more days to complete the task alone than it would take machine B to complete the task

Answer:

Machine A, working alone, can complete the task in 15 days.

Explanation:

As the average is given as 12.5 so,

A+B=2*12.5

A+ B=25

second condition says machine A takes 5 more days to complete the task alone than B so

A=B+5........Eq1

Now from the question statement we can get that

1/A+1/B=1/6, where A is time needed for A to do the task alone and B is the time needed for B to complete the task alone

thus, simplyfing above equation we get as

AB/A+B=6; \\ putting A+B=25 we get

AB/25=6

AB=6*25

AB=150; \\ putting Eq1 we get

(B+5)B=150

B^2+5B-150=0

simplifying the quadratic equation above we get B=10

putting B=10 in Eq1, we get

A+10=25

A=15

Thus, Machine A, working alone, can complete the task in 15 days.

3 0
3 years ago
1. A fixed pulley is a machine that increases the effort force.
IRISSAK [1]

For the specific questions given, these would be the answers:

1) False

2) False

3) True

4) True

5) True

I am hoping that these answers have satisfied your queries and it will be able to help you, thank you and have a nice day.

6 0
3 years ago
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