Answer:
The correct option is;
The star is moving toward Earth.
Explanation:
The shifting of the wavelength of light wave toward the blue end of the electromagnetic spectrum is termed blue shift.
A blue-shift of an electromagnetic wave corresponds to the wavelength decrease of the wave, which is equivalent increase in energy, resulting in an increase in the observed frequency of the wave.
Astronomers make use of the shifting of the wavelength of a wave to understand the relative motion of galaxies.
The wavelength of an approaching electromagnetic ave shifts towards the blue end of the electromagnetic spectrum because the wavelength is shorter.
The opposite of phenomenon is red-shift.
The average speed of the ball is 0.15 m/s.
The average speed of the ball can be calculated using the formula below.
<h3 /><h3> Average speed: </h3>
This is the ratio of the total distance to the total time traveled by a body
<h3 /><h3>Formula:</h3>
- S = d/t.................. Equation 1
<h3>Where:</h3>
- S = Average speed
- d = total distance
- t = total time.
From the question,
<h3>Given:</h3>
Substitute these values into equation 1
Hence, the average speed of the ball is 0.15 m/s.
Learn more about average speed here: brainly.com/question/4931057
An astronomical unit is the measure of the center of the Earth to the center of the sun.
Because our solar system is so vast, using mere miles is ridiculous, because they are too small to be helpful and the numbers will be in the billions. Astronomical units make it easier to think in small amounts.
Hope this helps :)
Is this a actual question? And what subject is this? Why are they using kids for nature?! I think NO! Not a good candidate
Answer:
A) r = 0.03 m
B) r = 0.0533 m
C) B_max = 0.00003 T
Explanation:
Formula for magnetic field inside the capacitor when it is parallel to the length element is;
B_in = (μ_o•I•r/(2πR²)
Formula for maximum magnetic field is;
B_max = (μ_o•I/(2πR)
Formula for magnetic field outside the capacitor is; B_out = (μ_o•I/(2πr)
A) Magnetic field inside the capacitor is gotten from our first equation above;
B_in = (μ_o•I•r/R²)
Since we want to find the radius at which the magnitude of the induced magnetic field equal to 75% or 0.75 of its maximum value.
Thus;
B_in = 0.75B_max
(μ_o•I•r/(2πR²) = 0.75((μ_o•I/(2πR))
μ_o•I and 2πR will cancel out to give;
r/R = 0.75
r = 0.75R
We are given R = 40 mm = 0.04 m
r = 0.75 × 0.04
r = 0.03 m
B) magnetic field outside the capacitor is; B_out = (μ_o•I/(2πr)
Thus for the magnitude of the induced magnetic field equal to 75% or 0.75 of its maximum value:
B_out = 0.75B_max
(μ_o•I/(2πr) = 0.75((μ_o•I/(2πR))
μ_o•I and 2π will cancel out to give;
1/r = 0.75/R
r = R/0.75
r = 0.04/0.75
r = 0.0533 m
C) B_max = μ_o•I/(2πR)
μ_o is a constant known as vacuum of permeability with a value of 4π × 10^(-7) T.m/A
Thus;
B_max = (4π × 10^(-7) × 6)/(2π × 0.04)
B_max = 0.00003 T
