As this procedure is carried out in the natural habitats of this species, this is an <em>in-situ conservation</em>.
<em>In-situ conservation </em>is the type of conservation that occurs on site, where the natural populations of plants or animals are found.
Answer: Option A.
It lowers the head.
Explanation:
The ischial arch is a prominent structure closer to the colliculus seminalis of horse. The ejaculatory duct is lateral to this and correspond to the area of ductus differenc eand vesicular gland opening.
The vesicular glands can be easily catheterized using a small-diammeter, flexible polyethylene catheter or a stylet . The catheter is inserted into the instrument channel of the videoendoscope and serves as a route for direct aspiration of fluid or instillation of pharmacologic solutions for direct treatment.It also helps to guide the scope head into the seminal vesicle .
I know that in identical twins, their genetics are much more alike :)
Answer:
C)Parental: 41% Dr, 41% dR; recombinant: 9% DR, 9% dr.
Explanation:
The notation Dr/dR for genotypes means that one homologous chromosome has the alleles Dr and the other homologous chromosome has the alleles dR.
The heterozygous plant Dr/dR will produce 4 types of gametes: two identical to the chromosmes the individual has in its somatic cells (called parental), and two gametes which will be a mix of the alleles in the homologous chromosomes (called recombinant).
- Dr: parental
- dR: parental
- DR: recombinant
- dr: recombinant
To calculate the frequency of each type of gamete, we must use the formula:
Distance (map units) / 100 = frequency of recombination.
18 mu / 100 = 0.18.
The total frequency of recombination between the genes D and R is 0.18, but every time crossing over happens, two recombinant gametes are generated. Therefore, each recombinant gamete will have a frequency of 0.18/2=0.09 = 9%.
The frequency of parental gametes will be:
1 - frequency of recombinant gametes
1 - 0.18 = 0.82
But there are 2 parental gametes, so each of them will have a frequency of 0.82/2=0.41 = 41%.