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aleksandrvk [35]
3 years ago
11

Amy simplifed this complex fraction problem. Negative 2 and one-half divided by five-fourths = Negative five-halves divided by f

ive-fourths = negative five-halves (five-fourths) = negative StartFraction 10 over 8 EndFraction. The quotient is negative five-fourths. What errors did Amy make? Select all that apply.
Mathematics
2 answers:
Alona [7]3 years ago
8 0

Answer:

B, C

Step-by-step explanation:

Amy should have flip the numerator and the denominator of the second fraction before multiplying. She also used addition instead of multiplication for the numerators.

Dmitry [639]3 years ago
5 0

Answer:

B,C

Step-by-step explanation:

Amy should have flipped the numerator and the denominator of the second fraction before multiplying. She also used addition instead of multiplication for the numerators.

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baherus [9]

A function that gives the amount that the plant earns per man-hour t years after it opens is \mathrm{A}(\mathrm{t})=80 \times 1.05^{\mathrm{t}}

<h3><u>Solution:</u></h3>

Given that  

A manufacturing plant earned $80 per man-hour of labor when it opened.

Each year, the plant earns an additional 5% per man-hour.

Need to write a function that gives the amount A(t) that the plant earns per man-hour t years after it opens.  

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As it is given that each year, the plants earns an additional of 5% per man hour

So Amount earned by plant after one year = $80 + 5% of $80 = 80 ( 1 + 0.05) = (80 x 1.05)

Amount earned by plant after two years is given as:

=(80 \times 1.05)+5 \% \text { of }(80 \times 1.05)=(80 \times 1.05)(1.05)=80 \times 1.052

Similarly Amount earned by plant after three years =80 \times 1.05^{t}

\begin{array}{l}{\Rightarrow \text { Amount earned by plant after } t \text { years }=80 \times 1.05^{t}} \\\\ {\Rightarrow \text { Required function } \mathrm{A}(t)=80 \times 1.05^{t}}\end{array}

Hence a function that gives the amount that the plant earns per man-hour t years after it opens is \mathrm{A}(t)=80 \times 1.05^{t}

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