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lianna [129]
3 years ago
5

Find the value of sin T rounded to the nearest hundredth, if necessary.

Mathematics
2 answers:
____ [38]3 years ago
7 0
Correct answer to your question is 0.6
katovenus [111]3 years ago
6 0
<h3>Answer:  0.6</h3>

========================================

Work Shown:

sin(angle) = opposite/hypotenuse

sin(T) = VU/VT

sin(T) = 3/5

sin(T) = 0.6

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Formula that relates the mass of an object at rest and its mass when it is moving at a speed v:

m=\frac{m_o}{\sqrt{1-\frac{v^2}{c^2}}}

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m = mass of the oebjct in motion

m_o = mass of the object when at rest

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We have :

1) Mass of the Dave = m_o=66 kg

Velocity of Dave ,v= 90% of speed of light = 0.90c

Mass of the Dave when moving at 90% of the speed of light:

m=\frac{66 kg}{\sqrt{1-\frac{(0.90c)^2}{c^2}}}

m = 151.41 kg

Mass of Dave when when moving at 90% of the speed of light is 151.41 kg.

2) Velocity of Dave ,v= 99% of speed of light = 0.99c

Mass of the Dave when moving at 99% of the speed of light:

m=\frac{66 kg}{\sqrt{1-\frac{(0.99c)^2}{c^2}}}

m = 467.86 kg

Mass of Dave when when moving at 99% of the speed of light is 467.86 kg.

3) Velocity of Dave ,v= 99.9% of speed of light = 0.999c

Mass of the Dave when moving at 99.9% of the speed of light:

m=\frac{66 kg}{\sqrt{1-\frac{(0.999c)^2}{c^2}}}

m = 1,467.17 kg

Mass of Dave when when moving at 99.9% of the speed of light is 1,467.17 kg.

4) Mass of the Dave = m_o=66 kg

Velocity of Dave,v=?

Mass of the Dave when moving at v speed of light: 500

500 kg=\frac{66 kg}{\sqrt{1-\frac{(v)^2}{(3\times 10^8 m/s)^2}}}

v=2.973\times 10^8 m/s

Dave should be moving at speed of 2.973\times 10^8 m/s.

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