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2 years ago

7

Ahmad deposits $6000 into an account that pays simple interest at a rate of 5% per year. How much interest will he be paid in th

e first 3 years

1 answer:

jasenka [17]2 years ago

5 0

He will pay 900 on the first 3 years

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Two mechanics worked on a car. The first mechanic worked for 15 hours, and the second mechanic worked for 5 hours. Together they

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Now this may or may not be work I’m 99.9 percent sure it’s right but if not sorry

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3 years ago

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DedPeter [7]

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its between c or b

Step-by-step explanation:

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3 years ago

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Which of the following points lie in the solution set to the following system of inequalities? y < −3x + 3 y < x + 2

sweet-ann [11.9K]

Answer:

$y < 6 \\ x < 4 \\$

$x( \frac{3y}{?4} - \frac{1}{2?} \frac{2y}{?3} )y < 6 \\ y( \frac{3x}{?2} 4x + \frac{2}{?3} )x < 4$

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3 years ago

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The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p

VLD [36.1K]

Answer:

$3.13$

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

$\chi^2_{1-\frac{\alpha}{2}}= 51.770$

Chi square critical value for upper tail =

$\chi^2_{\frac{\alpha}{2}}= 81.085$

80% confidence interval:

$\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}$

Putting values, we get,

$=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13$

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0

3 years ago

If y = 3x^3 - 2x and dx/dt equals 3, find dy/dt when x = -2. Give only the numerical answer. For example, if dy, dt = 4, type on

Nadya [2.5K]

Answer:

$\frac{dy}{dt} = 102$

Step-by-step explanation:

<u>step(i)</u>

Given function y = 3 x³ - 2 x ... (i)

Differentiating equation (i) with respective to 'x'

$\frac{dy}{dx} = 3 (3 x^{2} ) - 2(1)$

Given x = -2

$(\frac{dy}{dx} ) x_{=-2} = 3 (3 (-2)^{2} ) - 2(1)$

$(\frac{dy}{dx} ) x_{=-2} = 36 -2 =34$

<u><em>Step(ii):-</em></u>

<u><em>we know that </em></u>

$\frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

Given $\frac{dx}{dt} = 3 and \frac{dy}{dx} = 34$

$\frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

substitute values $\frac{dx}{dt} = 3 and \frac{dy}{dx} = 34$

⇒ $34 = \frac{\frac{dy}{dt} }{3 }$

cross multiplication , we get

$\frac{dy}{dt} = 34( 3 ) = 102$

<u><em>Final answer</em></u>:-

$\frac{dy}{dt} = 34( 3 ) = 102$

8 0

3 years ago