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Tpy6a [65]
3 years ago
11

Find the chemical formulas for three vitamins and identify two elements found in each.

Physics
1 answer:
vladimir1956 [14]3 years ago
3 0
1.Vitamin C   (ascorbic acid)
Chemical formula of vitamin C is C6H8O6
Two elements found in  vitamin C are Carbon and Hydrogen

2. Vitamin B12   (Cyanocobalamin)
Chemical formula of vitamin B12 is  C63H88CoN14O14P
Two elements found in vitamin B12  are Phosphorous and Cobalt. Of these two elements, Cobalt is a trace element  and is found right at the center of this vitamin.

3. Vitamin E   (alpha-Tocopherol)
Chemical formula of vitamin E is C29H50O2
Two elements found in vitamin E are Hydrogen and Oxygen.






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3. Planet 1 has mass M₁ and radius R₁. Planet 2 has mass M₂ and radius
Oksanka [162]

(a) The initial speed must the object be launched so that it reaches

the surface of Planet 2 with zero speed is  √[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}]

(b) An inequality between M₁ and M₂ that represents when (a)

can occur is { M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0

(c)  if R₁ = R₂, then M₁ must be greater than M₂ is proved.

<h3>What is gravity?</h3>

The force of attraction felt by a person which is directed at the center of a planet or Earth is called as the gravity.

The force of attraction is directly proportional to the product of masses of the object and inversely proportional to the square of distance between them.

F = GMm/R²

Given, Planet 1 has mass M₁ and radius R₁. Planet 2 has mass M₂ and radius R₂. The two planets are a distance of L apart, measured from surface to surface. An object is launched with some initial speed from the surface of Planet 1 directly towards Planet 2. For this problem, assume that Planets1 and 2 are stationary.

If v is the launch velocity, then initial total energy will be

T.E  = 1/2 mv² + ( -GM₁m/ R₁ - G M₂m/(R₂ + L)

The final total energy will be

T.E  =0 + ( -GM₁m/ (R₁ +L) - G M₂m/ R₂)

From energy conservation principle, we get

1/2 mv² + ( -GM₁m/ R₁ - G M₂m/(R₂ + L) = ( -GM₁m/ (R₁ +L) - G M₂m/ R₂)

v = √[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}]

(b) an inequality between M₁ and M₂  so that object reaches the surface of Planet 2 with zero speed is

[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}] =0

{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0

Thus, this is an inequality between M₁ and M₂.

(c) If R₁ = R₂, then

{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0

M₁(R+L) + M₂R - M₁R  -M₂(R+L) / R (R+L)   ≥ 0

M₁(R+L) + M₂R - M₁R  -M₂(R+L)  ≥ 0

M₁L - M₂L  ≥ 0

M₁ ≥ M₂

M₁ must be greater than M₂.

Learn more about gravity.

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8 0
2 years ago
Describe the relationship between the potential and kinetic energies of the tennis ball as it travels the length of the roller c
RSB [31]
If we neglect frictional force, the total mechanical energy of the ball is conserved.
The total mechanical energy of the ball is the sum of its kinetic energy K and its potential energy U:
E=K+U
where the kinetic energy depends on the speed v of the ball: 
K= \frac{1}{2} mv^2 
while the potential energy depends on the height h at which the ball is:
U=mgh

As the ball travels along the roller coaster, there is a continuous conversion between kinetic and potential energy, because the total mechanical energy E has always the same value. Therefore, when the ball goes on top of a hill, its height h increases and its potential energy U increases as well, while the speed v decreases and K decreases. Vice-versa, when the ball reaches the bottom of a hill, its height h decreases and therefore the potential energy U decreases, while the speed v increases and therefore the kinetic energy K of the ball increases as well.
8 0
4 years ago
An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about _____ years.
Airida [17]

Answer:

An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about  2 years.

Explanation:

Given;

orbital period of 3 years, P = 3 years

To calculate the years of an orbital with a semi-major axis, we apply Kepler's third law.

Kepler's third law;

P² = a³

where;

P is the orbital period

a is the orbital semi-major axis

(3)² = a³

9 = a³

a = a = \sqrt[3]{9} \\\\a = 2.08 \ years

Therefore, An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about  2 years.

5 0
3 years ago
To maximize the percentage of the power from the emf of a battery that is delivered to a device, what should the internal resist
Simora [160]

To maximize the power delivered to load, we should minimize the internal resistance which means option A is correct.

<h3>What is the relationship between the power and the internal resistance?</h3>

Power  can be  delivered to the internal resistance of a battery, but in a case whereby there is a decrease in the internal resistance will bring about the decrease in the  lost power  as well as the  increase in  the percentage of the power delivered to the device.

In this case, To maximize the power delivered to load, we should minimize the internal resistance

Therefore, Option A is correct.

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3 0
2 years ago
How much power would be needed to lift a 1.0x10^3N crate 1.5m in 5 seconds?
lina2011 [118]

Answer:power =300watts

Explanation:

5 0
4 years ago
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