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3 years ago

As an object rolls downhill, some of the energy is

2 answers:

7 0

When the object is at the top of the hill it has the most potential energy. If it is sitting still, it has no kinetic energy. As the object begins to roll down the hill, it loses potential energy, but gains kinetic energy. The potential energy of the position of the object at the top of the hill is getting converted into kinetic energy. Hope this helped. :)

mr_godi [17]3 years ago

6 0

Well this is kind of a trick question. When the object is still before it rolls downhill it is potential. But as the object is rolling down the hill, it is kinetic energy. So, I believe your answer would be kinetic since it doesn't specify everything that's happening.

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Two 3.0 μC charges lie on the x-axis, one at the origin and the other at What is the potential (relative to infinity) due to the

miskamm [114]

Complete Question:

Two 3.0µC charges lie on the x-axis, one at the origin and the other at 2.0m. A third point is located at 6.0m. What is the potential at this third point relative to infinity? (The value of k is 9.0*10^9 N.m^2/C^2)

Answer:

The potential due to these charges is 11250 V

Explanation:

Potential V is given as;

$V =\frac{Kq}{r}$

where;

K is coulomb's constant = 9x10⁹ N.m²/C²

r is the distance of the charge

q is the magnitude of the charge

The first charge located at the origin, is 6.0 m from the third charge; the potential at this point is:

$V =\frac{9X10^9 X3X10^{-6}}{6} =4500 V$

The second charge located at 2.0 m, is 4.0 m from the third charge; the potential at this point is:

$V =\frac{9X10^9 X3X10^{-6}}{4} =6750 V$

Total potential due to this charges = 4500 V + 6750 V = 11250 V

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4 years ago

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Anna [14]

Answer:

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Answer:

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Answer:

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Explanation:

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You are working on a proof. You know that A and B are on the perpendicular bisector of CD. What can you conclude?

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A point on the perpendicular bisector of a line segment
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So
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This can sometimes be very useful.

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4 years ago

Read 2 more answers