Someone please help me!
1 answer:
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Answer:
A) ( - 200t + 40 ) volts
B) b) anticlockwise , c) anticlockwise , d) clockwise , e) clockwise
Explanation:
Given data:
magnetic flux (Φm) = 5.0t^2 − 2.0t
number of turns = 20
<u>a) determine induced emf </u>
E = - N
= - N ( 10t - 2 ) = - 20 ( 10t - 2 )
= - 200t + 40 volts
<u>b) Determine direction of induced current </u>
i) at t = 0
E = - 0 + 40 ( anticlockwise direction )
ii) at t = 0.10
E = -20 + 40 = 20 ( anticlockwise direction )
iii) at t = 1
E = - 200 + 40 = - 160 ( clockwise direction)
iv) at t = 2
E = -400 + 40 = - 360 ( clockwise direction )
Answer:
This means that the center of mass is locates 0.72m from the 750N force
Explanation:
Since the board is 2.2m long, that will be the length of the board.
Let the center of mass of the body be hinged at the center using a knife edge as shown in the diagram attached.
Let x be the distance from the 750N force to the knife edge and the distance from the 360N force to the knife edge be 2.2-x
Using the principle of moment which states that the sum of clockwise moment is equal to the sum of anti clockwise moment.
Moment = force × perpendicular distance
For ACW moment;
Moment = 750×x = 750x
For the CW moment;
Moment = 360 × (2.2-x)
Moment = 792-360x
Equating ACW moment to the clockwise moment we have;
750x = 792-360x
750x+360x = 792
1110x = 792
x = 792/1110
x = 0.72m
This means that the center of mass is locates 0.72m from the 750N force
