First of all, x>y
x-y=40
and
x+y=66
add them equations together to eliminate
x-y=40
<u>x+y=66 +</u>
2x+0y=106
2x=106
divide by 2
x=53
sub back
x-y=40
53-y=40
minus 53 both sides
-y=-13
y=13
the numbers are 53 and 13
Use Pythagorean Theorem: a^2+b^2=c^2.
It's C)
the graph is decrasing, so the variable rate is negative (-2/3)
the rest was quite easy, you just take a look at where the graph cuts the y-axis and determine the rest from the rate of going up or down (increase/decrease)
Answer:
y= -7
Step-by-step explanation:
y=ax+b
Find a where a=y2-y1 /x2-x1
y2=13,y1=5 x2=5,x1=3
substituting the values
a=13-5/5-2
a=8/2
a=4
substituting a into the formular
y=4x+b
taking x and y values let say 3 and 5 for x and y
the equation becomes
5=4(3)+b
5=12+b
5-12=b
-7=b
substituting the values of a and b into the equation
y=4x-7
when x=0
y=4(0)-7
y=0-7
y=-7
so when x=0,y=-7
Okay, here we have this:
Considering the provided information, we are going to calculate the requested value, so we obtain the following:
Then we will substitute in the following formula:
Students who play soccer=Number of students*(Probability that they play soccer)
Replacing:
Students who play soccer=300*(12/25)
Students who play soccer=3600/25
Students who play soccer=144
Finally we obtain that 144 students would we expect to play soccer, based on Sean's experiment.
