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statuscvo [17]
3 years ago
10

How many terms are in this expression? 1 + 9 + 3u Submit

Mathematics
1 answer:
lana [24]3 years ago
5 0

Answer:

2

Step-by-step explanation:

When it comes to like terms, they have to end with the same symbol A.K.A variables, exponents, and numbers.

1 + 9 + 3u

There are two terms, constants and variables, constant being 1 and 9 while variable being 3u.

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To find a reciprocal of a fraction, switch the numerator and denominator.
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The reciprocal of -1/3 is -3/1
and the reciprocal of 4/1 is 1/4
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3 years ago
Sub tract 13/15 -1/5
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It would be .6 repeating
6 0
3 years ago
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Verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3. Also verify the relationship between the ze
Finger [1]

Solution:

we have been asked to verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3

To verify that whether the given values are zeros or not we will substitute the values in the given Polynomial, if it will returns zero, it mean that value is Zero of the polynomial. But if it return any thing other than zeros it mean that value is not the zero of the polynomial.

Let f(x)=4x^3+20x^2+2x-3\\\\\text{when x=-5}\\\\f(-5)=4(-5)^3+20(-5)^2+2(-5)-3=-13\\\\\text{when x=}\frac{1}{2}\\

f( \frac{1}{2} ) = 4 ( \frac{1}{2} )^3+20(\frac{1}{2})^2+2(\frac{1}{2})-3=\frac{7}{2}\\\\

\text{when x=}\frac{3}{4}\\\\

f( \frac{3}{4} ) = 4 ( \frac{3}{4} )^3+20(\frac{3}{4})^2+2(\frac{3}{4})-3=\frac{183}{16}\\

Hence -5, 1/2, and 3/4 are not the zeroes of the given Polynomial.

Since sum of roots=\frac{-b}{a}= \frac{-20}{4}=-5\\

But -5+\frac{1}{2}+\frac{3}{4}=  \frac{-15}{4}\neq-5

Hence we do not find any relation between the coefficients and zeros.

Anyway if the given values doesn't represents the zeros then those given values will not have any relation with the coefficients of the p[polynomial.

6 0
3 years ago
Pls help. What is the appropriate congruent for these triangles
tekilochka [14]

Answer:

ASA

Step-by-step explanation:

In given triangle

Line BC = Line QR

Angle ABC = Angle PQR

Angle ACB = Angle PRQ

Computation:

Angle ABC = Angle PQR (Angle)

Line BC = Line QR (Side)

Angle ACB = Angle PRQ (Angle)

So,

ΔABC ≅ ΔPQR

By Angle Side Angle property

ASA

5 0
2 years ago
Ajax is 5 and 1 fourth feet tall. His sister is 3 eighths foot shorter than Ajax How tall is Ajax Sister?
user100 [1]

Answer:

4\frac{3}{4} feet tall

Step-by-step explanation:

Ajax is "5 and 1 fourth feet tall", which can be written as the mixed number 5\frac{1}{4} .

His sister is "3 eighths foot shorter", so she's 3/8 feet shorter than 5 1/4.

So, this is just a subtraction problem:

5\frac{1}{4} -\frac{3}{8}

To solve this, we want to convert 5 1/4 into an improper fraction, which is: \frac{21}{4} . Now, we want to find a common denominator. In this case, that common denominator is 8, so \frac{21}{4} =\frac{42}{8} .

Finally, we subtract 3/8 from 42/8: \frac{42}{8} -\frac{3}{8} =\frac{39}{8} . So, Ajax's sister is 39/8 feet. Converting this into a mixed number, we have: 39/8 = 4\frac{6}{8} =4\frac{3}{4} .

Therefore, Ajax's sister is 4\frac{3}{4} feet tall.

Hope this helps!

7 0
3 years ago
Read 2 more answers
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