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statuscvo [17]
3 years ago
10

How many terms are in this expression? 1 + 9 + 3u Submit

Mathematics
1 answer:
lana [24]3 years ago
5 0

Answer:

2

Step-by-step explanation:

When it comes to like terms, they have to end with the same symbol A.K.A variables, exponents, and numbers.

1 + 9 + 3u

There are two terms, constants and variables, constant being 1 and 9 while variable being 3u.

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I think the area is 30 units
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What is the y-coordinate of the solution of the system of equations? {y=3x−262x−y=19 Enter your answer in the box.
Yuki888 [10]

Answer:

<h2>y = -5</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}y=3x-26&(1)\\2x-y=19&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\2x-(3x-26)=19\\2x-3x+26=19\qquad\text{subtract 26 from both sides}\\-x=-7\qquad\text{change the signs}\\x=7\\\\\text{Put the value of x to (1):}\\\\y=3(7)-26=21-26=-5

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3 years ago
Box 1 contains 2 red balls and 1 blue ball. Box 2 contains 3 blue balls and 1 red ball. A coin is tossed. If it falls heads up,
vlada-n [284]

Answer:

\frac{17}{24}

Step-by-step explanation:

Given that Box 1 contains 2 red balls and 1 blue ball. Box 2 contains 3 blue balls and 1 red ball. A coin is tossed. If it falls heads up, box 1 is selected and a ball is drawn. If it falls tails up, box 2 is selected and a ball is drawn.

P(selecting Box 1) = 0.5 = P(selecting II box) (assuming a fair coin is tossed)

P(Red/Box I ) = \frac{2}{2+1} =\frac{2}{3}

P(Red/Box II) = \frac{3}{3+1} =\frac{3}{4}

Box 1 and Box 2 are mutually exclusive and exhaustive events.

So probability of selecting a red ball.

=  probability of selecting a red ball from box 1 +  probability of selecting a red ball frm box 2

=P(B1)*P(Red/B1) + P(B2)*P(Red/B2)\\= \frac{1}{2} * \frac{2}{3} + \frac{1}{2} * \frac{3}{4} \\= \frac{1}{3} + \frac{3}{8} \\= \frac{17}{24}

7 0
4 years ago
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Answer:

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4 0
3 years ago
PLEASE HELP!! I'LL GIVE YOU BRAINLIEST !!
kondor19780726 [428]

Answer:

1 ) a    2) b    3) d    4) b    5) a    6) c

Step-by-step explanation:

8 0
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